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2 years ago

Help me solve for x and y .

Mathematics

2 answers:

Olegator [25]2 years ago

7 0

Answer:

Step-by-step explanation:

adell [148]2 years ago

5 0

Answer:

x = 20
y = 114°

Step-by-step explanation:

An exterior angle of a triangle is equal to the sum of the remote interior angles.

(3x +6)° = 31° +35°

3x +6 = 66 . . . . . . . . . . divide by °, collect terms

3x = 60 . . . . . . . . subtract 6

x = 20 . . . . . . . divide by 3

The value of y is the supplement of (3x+6)°, and of the sum (31 +35)°.

y = 180° -66° = 114°

The values of x and y are 20 and 114°, respectively.

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You draw two cards from a standard deck of 52 cards. What is the probability of drawing a club and then a diamond consecutively

otez555 [7]

Answer:

There are 13 cards for each suit so the first fraction is 13/52 and the next one is 13/51 as there is no replacement for the first card you pulled.

Multiplying them you get: 13/52*13/51= 169/2652,

Then you divide both sides by 13 to get: 13/204

So, the answer is C.

I hope this helps!

5 0

3 years ago

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Exercise 7.3.5 The following is a Markov (migration) matrix for three locations        1 5 1 5 2 5 2 5 2 5 1 5 2 5 2 5 2

fredd [130]

Answer:

Both get the same results that is,

$\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

Step-by-step explanation:

Given :

$\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

and initial population,

$\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]$

a) - After two times, we will find in each position.

$P_2=[P].[M]^2=[P].[M].[M]$

$M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]$

$=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

b) - With in migration process, 500 people are numbered. There will be after a long time,

$After\;inifinite\;period=[M]^n.[P]$

$Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]$

$=\left[\begin{array}{ccc}140\\160\\200\end{array}\right]$

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3 years ago

Help me solve 1 <2n-5 <_7 also please explain

Naddik [55]

I'm not sure if that is supposed to be 7 or -7 If it's -7: 1<2n-5<-7 +5 +5 +5 Add 5 to all parts of the inequality get 2n by itself 6<2n<-2 /2 /2 /2 Divide all parts by 2 to isolate the variable 3

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3 years ago

What is the equation of line perpendicular to y-3=-4(x+2) and passee through the point (-5,7

netineya [11]

Answer: $y=\frac{1}{4}x+\frac{33}{4}$

Step-by-step explanation:

1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.

2. The equation given in the problem is written in Point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope.

3. Therefore, the slope of its perpendicular line must be:

$m=\frac{1}{4}$

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

$y-7=\frac{1}{4}(x+5)$

5. In slope intercept form is:

$y=\frac{1}{4}x+\frac{5}{4}+7\\y=\frac{1}{4}x+\frac{33}{4}$

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3 years ago

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Zolol [24]

Answer:

Step-by-step explanation:

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2 years ago

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