Answer:
There are 13 cards for each suit so the first fraction is 13/52 and the next one is 13/51 as there is no replacement for the first card you pulled.
Multiplying them you get: 13/52*13/51= 169/2652,
Then you divide both sides by 13 to get: 13/204
So, the answer is C.
I hope this helps!
Answer:
Both get the same results that is,
![\left[\begin{array}{ccc}140\\160\\200\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D140%5C%5C160%5C%5C200%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given :
![\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]](https://tex.z-dn.net/?f=%5Cbf%20M%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D)
and initial population,
![\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]](https://tex.z-dn.net/?f=%5Cbf%20P%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D130%5C%5C300%5C%5C70%5Cend%7Barray%7D%5Cright%5D)
a) - After two times, we will find in each position.
![P_2=[P].[M]^2=[P].[M].[M]](https://tex.z-dn.net/?f=P_2%3D%5BP%5D.%5BM%5D%5E2%3D%5BP%5D.%5BM%5D.%5BM%5D)
![M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]](https://tex.z-dn.net/?f=M%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D)
![=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B25%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%267%267%5C%5C8%268%268%5C%5C10%2610%2610%5Cend%7Barray%7D%5Cright%5D)
![\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]](https://tex.z-dn.net/?f=%5Ctherefore%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3BP_2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%267%267%5C%5C8%268%268%5C%5C10%2610%2610%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D130%5C%5C300%5C%5C70%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D140%5C%5C160%5C%5C200%5Cend%7Barray%7D%5Cright%5D)
b) - With in migration process, 500 people are numbered. There will be after a long time,
![After\;inifinite\;period=[M]^n.[P]](https://tex.z-dn.net/?f=After%5C%3Binifinite%5C%3Bperiod%3D%5BM%5D%5En.%5BP%5D)
![Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]](https://tex.z-dn.net/?f=Then%2C%5C%3Bwe%5C%3Bget%5C%3Bthe%5C%3Bsame%5C%3Bresult%5C%3Bif%5C%3Bwe%5C%3Bmeasure%20%5BM%5D%5En%3D%5Cfrac%7B1%7D%7B25%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%267%267%5C%5C8%268%268%5C%5C10%2610%2610%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{ccc}140\\160\\200\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D140%5C%5C160%5C%5C200%5Cend%7Barray%7D%5Cright%5D)
I'm not sure if that is supposed to be 7 or -7
If it's -7:
1<2n-5<-7
+5 +5 +5 Add 5 to all parts of the inequality get 2n by itself
6<2n<-2
/2 /2 /2 Divide all parts by 2 to isolate the variable
3
Answer: 
Step-by-step explanation:
1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.
2. The equation given in the problem is written in Point-slope form:

Where m is the slope.
3. Therefore, the slope of its perpendicular line must be:

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

5. In slope intercept form is:

Answer:
90
Step-by-step explanation:
In a box plot, the point farthest to the line is the greatest or maximum number of the problem(in this case E). You look for the greatest number out of them all and that would be your answer(90).
Can i pretty please with a cherry on top get brainliest??
:>