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2 years ago

Write an equation to represent the following statement. 51 5151 divided by 3 33 is k kk.

Mathematics

1 answer:

enot [183]2 years ago

6 0

The equation is a quotient statement, and the equation is 51/3 = k

<h3>How to determine the equation?</h3>

The statement is given as:

51 divided by 3 is k

Represent the word "is" with "="

So, we have:

51 divided by 3 = k

Represent the word "divided" with "/"

So, we have:

51 / 3 = k

Hence, the equation is 51/3 = k

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a student found the volume of a rectangular pyramid with a base area of 92 square meters and a height of 54 Meters to be 4968 cu

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It is not correct.

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3 years ago

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Answer:

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Step-by-step explanation:

=-13.9+(-12.8)

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2 years ago

Suppose 10000 people are given a medical test for a disease. About1% of all people have this condition. The test results have a

Alina [70]

Answer:

The percent of the people who tested positive actually have the disease is 38.64%.

Step-by-step explanation:

Denote the events as follows:

X = a person has the disease

P = the test result is positive

N = the test result is negative

Given:

$P(X)=0.01\\P(P|X^{c})=0.15\\P(N|X)=0.10$

Compute the value of P (P|X) as follows:

$P(P|X)=1-P(P|X^{c})=1-0.15=0.85$

Compute the probability of a positive test result as follows:

$P(P)=P(P|X)P(X)+P(P|X^{c})P(X^{c})\\=(0.85\times0.10)+(0.15\times0.90)\\=0.22$

Compute the probability of a person having the disease given that he/she was tested positive as follows:

$P(X|P)=\frac{P(P|X)P(X)}{P(P)}=\frac{0.85\times0.10}{0.22} =0.3864$

The percentage of people having the disease given that he/she was tested positive is, 0.3864 × 100 = 38.64%.

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2 years ago