Yes 12-13 hope this helps you
5*1/5+1/5*15=4
1 + 3 =4
This should equal 4 if I did this correctly.
The correct answer is BN.
The roots of an equation are simply the x-intercepts of the equation.
See below for the proof that has at least two real roots
The equation is given as:
There are several ways to show that an equation has real roots, one of these ways is by using graphs.
See attachment for the graph of
Next, we count the x-intercepts of the graph (i.e. the points where the equation crosses the x-axis)
From the attached graph, we can see that crosses the x-axis at approximately <em>-2000 and 2000 </em>between the domain -2500 and 2500
This means that has at least two real roots
Read more about roots of an equation at:
brainly.com/question/12912962
Answer:
100/9
Step-by-step explanation:
(7*5*2/7*3)² * (5^0/2^-3)³ * 2^-9
Solution:
We know that any number with power 0 = 1
(7*5*2/7*3)² * (1/2^-3)³ * 2^-9
Now cancel out 2 by 2
= (7*5*2/7*3)² * (1/1^-3)³ * 1^-9
=(70/21)² * (1)³/(1^-3)³ * 1^-9
=(10/3)^2 * 1/1^-1 * 1/1^9
=100/9 *1 *1
=100/9....