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Rainbow [258]
1 year ago
7

Find the missing side

Mathematics
1 answer:
miv72 [106K]1 year ago
3 0

Answer:

18

Step-by-step explanation:

yes

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Part 2. State what additional information is required in order to know that the triangles are congruent by ASA.​
Helga [31]
<h3>Answer: Choice D. \angle SQR \cong \angle XQR</h3>

The red angle markers show those two angles are congruent. That's one "A" of "ASA". The S refers to a congruent pair of sides. We don't have any tickmarks to indicate congruent pairs; however, we do know that QR = QR is a shared side that overlaps (reflexive theorem). So this is the "S" in "ASA".

The thing missing is the angle Q of the top triangle, and also of the bottom triangle as well. If we know those two angles are congruent, then we have enough info to use ASA. More specifically, if we know that \angle SQR \cong \angle XQR, then we can use ASA.

One thing to notice is that the other answer choices involve side lengths and not angles. This implies that if A, B or C were one of the answers, then we would have something like SAS or SSS. But instead we want ASA. So we can immediately rule choices A,B, and C out.

7 0
3 years ago
The color of any object depends upon which colors are reflected and absorbed. True or False?
SSSSS [86.1K]

Answer:

true

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Which table corresponds to the graph of the function below?
likoan [24]

Answer:

I belive its the second 1

Step-by-step explanation:

kakalkjslkajslkjslkjalk

4 0
3 years ago
Read 2 more answers
Find the general solution of {y}''-3y=8e^{3t}+4sin(t) .
babunello [35]

Answer:

y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint

Step-by-step explanation:

We are given that linear differential equation

y''-3y=8e^{3t}+4 sint

Auxillary equation

D^2-3=0

D=\pm \sqrt3

C.F=C_1e^{\sqrt3t}+C_2e^{-\sqrt3}

P.I=\frac{8e^{3t}+4sin t}{D^2-3}

P.I=\frac{8e^{3t}}{9-3}+4\frac{sint }{-1-3}

P.I=e^{ax}{\phi (D+a)} and P.I=\frac{sinax}{(\phi D)}where D square is replace by - a square

P.I=-\frac{4}{3}e^{3t}- sint

Hence, the general solution

G.S=C.F+P.I

y(x)=C_1e^{\sqrt3t}+C_2e^{-\sqrt3t}-\frac{4}{3}e^{3t}-sint

3 0
3 years ago
Simplify the expression.
Sati [7]

Answer:

LAST OPTION: x^9

Step-by-step explanation:

For this exercise it is important to remember the Power of a power property, which states that:

(a^m)^n=a^{mn}

The expression given in the exercise is:

(x^\frac{3}{2})^6

Therefore, in order to simplify it, you  must apply the Power of a power property explained before.

Then, you get the following expression:

=x^{(\frac{3}{2}*6)}=x^{(\frac{3*6}{2})}=x^{\frac{18}{2}}=x^9

As you can notice, the expression obtained matches with the expression provided in the last option.

6 0
3 years ago
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