The ordered pair of the origin is (0,0)
Answer:
rs = -3/16 and the three minima x₁, x ₂ and x₄ fall at the value of integrating curve C
Step-by-step explanation:
The answer is found in the attachment.
Answer:
See below.
Step-by-step explanation:
a.
The first figure has 1 square. The second figure has a column of 2 squares added to the left. The third figure has a column of 3 squares added to the left. Each new figure has a column of squares added to the left containing the same number of squares as the number of the figure.
b.
Figure 10 has 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 55 squares.
c.
The formula for adding n positive integers starting at 1 is:
1 + 2 + 3 + ... + n = n(n + 1)/2
For figure 55, n = 55.
n(n + 1)/2 = 55(56)/2 = 1540
d.
Let's use the formula set equal to 190 and solve for n. If n is an integer, then we can.
n(n + 1)/2 = 190
n(n + 1) = 380
We know that 380 = 19 * 20, so n = 19.
Answer: yes
e.
Use the formula above,
S = n(n + 1)/2, where S is the sum.
f.
n(n + 1) = 1478
38 * 39 = 1482
37 * 38 = 1406
Answer:
radius = 5 units
area of a circle = 15.7units²
Step-by-step explanation:
given that the circumference of a circle = 31.4
radius = ?
recall that the formulae for finding the circumference of a circle = 2πr
circumference of a circle = 2 x 3.14 x r
31. 4 = 6.28r
divide both sides by the coefficient of r which is 6.28
31.4/6.28 = 6.28r/6.28
5 = r
radius = 5 units
therefore the radius of the circle whose circumference is 31.4 units is evaluated to be 5units
to find the area of the circle
recall the formula = πr²
area of a circle = 3.14 x 5²
area of a circle = 3.14 x 25
area of a circle = 15.7units²
I thinks it’s between A and B
