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san4es73 [151]
2 years ago
14

George spent exactly one dollar for some 5 cent stamps and some

Mathematics
1 answer:
Temka [501]2 years ago
3 0

Answer:

He bought 3.3 cents

Step-by-step explanation:

I hope I am right

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I know this is easy but what is 799 divided by 7
Mademuasel [1]

114.14

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3 years ago
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Bus A and Bus B leave the bus depot at 8 am.
LenaWriter [7]

Answer: 10:55

Step-by-step explanation:

Taking statement at face value and the simplest scenario that commencing from 08:00am the buses take a route from depot that returns bus A to depot at 25min intervals while Bus B returns at 35min intervals.

The time the buses will be back at the depot simultaneously will be when:

N(a) * 25mins = N(b) * 35mins

Therefore, when N(b) * 35 is divisible by 25 where N(a) and N(b) are integers.

Multiples of 25 (Bus A) = 25, 50, 75, 100, 125, 150, 175, 200 etc

Multiples of 35 (Bus B) = 35, 70, 105, 140, 175, 210, 245 etc

This shows that after 7 circuits by BUS A and 5 circuits by Bus B, there will be an equal number which is 175 minutes.

So both buses are next at Depot together after 175minutes (2hr 55min) on the clock that is

at 08:00 + 2:55 = 10:55

6 0
3 years ago
Help meh pwease <3 Have a great day y’all!
Alexxandr [17]

The first thing you would do is add all the numbers to get the total budget : $1500

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3 years ago
Please help!!!<br> Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3
Elza [17]
\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}

\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5
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3 years ago
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Estimate the quotient: 1628 ÷ 8
Pachacha [2.7K]

Answer:

203.5

Step-by-step explanation:

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3 years ago
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