Question

The function h(x) is given below:

Answer 1

Step-by-step explanation:

The domain and range of a function and its inverse are inverted i.e. The domain of the function will become range of its inverse and the range of the function will become the domain of its inverse.

When representing the function in ordered pairs, the first values in the pair represents the domain and second values represent the range of the function.

h(x) = {3,5),(5,-7)(6,-9)(10,-12)(12,16)}

Domain of h(x) is: {3, 5, 6, 10, 12}

Range of h(x) is: (5, -7, -9, -12, 16}

So,

Domain of $h^{-1}(x)$ = Range of h(x) = (5, -7, -9, -12, 16}

Range of $h^{-1}(x)$ = Domain of h(x) = {3, 5, 6, 10, 12}

Therefore, $h^{-1}(x)$ will be represented as:

{(5,3), (-7,5), (-9, 6), (-12, 10), (16,12)}

It seems like you have made some error while writing the original function because of which we are not getting an exact match in the answer. However by looking at the answers, option B is the nearest most and seems the correct answer.