The scores on a certain standardized test follow a normal distribution. The mean score is 76, and the standard deviation is 8.
1 answer:
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Answer:
Therefore, the correct options are;
-P(fatigue) = 0.44
= 0.533
--P(drug and fatigue) = 0.32
P(drug)·P(fatigue) = 0.264
Step-by-step explanation:
Here we have that for dependent events,
From the options, we have;
= 0.533
P(drug) = 0.6
P(drug and fatigue) = 0.32
Therefore
P(drug and fatigue) = P(drug)×
= 0.6 × 0.533 = 0.3198 ≈ 0.32 = P(drug and fatigue)
Therefore, the correct options are;
-P(fatigue) = 0.44
= 0.533
--P(drug and fatigue) = 0.32
P(drug)·P(fatigue) = 0.264
Since P(fatigue) = 0.44 ∴ P(drug) = 0.264/0.44 = 0.6.