It is 4009.738/!;7 corrects
The number of cars that sold on the third week is (P3=26)
The number of cars that sold on the first week is (P4=33)
<u>Step-by-step explanation:</u>
<u>Given:</u>
- The number of cars that sold on the first week is (P0=7)
- The number of cars that sold on the second week is (P0=12)
We have to find the number of cars being sold on the upcoming week
From the data given above, frame the equation
Pn = Pn −1+7 ( 12-5=7 it denotes the cars sold in the first and the second week)
Pn=5+7n (cars in the first week and the cars sold in the second week into "n" n is used to find the cars sold in the upcoming weeks)
(If n=3)
Pn=5+7(3)
Pn=26
The number of cars that sold on the third week is (P3=26)
(If n=4)
Pn=5+7(4)
Pn=33
The number of cars that sold on the first week is (P4=33)
<span>In 10 years, you will have $31,049.30</span>
He can shoot 6 because at this point we are diving 72 divided by 12 equals 6 hope it helps
See the attached image for the graph. Specifically figure 2 is the graph you want. You can leave the red points on the graph or decide to erase them (leave behind the blue line though).
To generate each of the red points, you'll plug in various x values to get corresponding y values.
For instance, plug in x = 0 and we get...
y = -|x-6| - 6
y = -|0-6| - 6
y = -|-6| - 6
y = -6 - 6
y = -12
So when x = 0, the y value is -12. The x and y value pair up to get (x,y) = (0,-12)
Another example: plug in x = 2
y = -|x-6| - 6
y = -|2-6| - 6
y = -|-4| - 6
y = -4 - 6
y = -10
So the point (2,-10) is on the graph
The idea is to generate as many points as possible so we get an idea of what this thing looks like.
Generate enough points, and you'll get what you see in Figure 1 (see attached image)
Then draw a line through all of the points. The more points you use, the more accurate the drawing. Doing that will generate the blue function curve you see in Figure 2 (also attached)