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SVEN [57.7K]
3 years ago
14

Automobile fuel efficiency is often measured in miles that the car can be driven per gallon of fuel (mpg). Heavier cars tend to

have lower fuel efficiencies (lower mpg ratings). Which variable (weight or fuel efficiency) is most naturally considered the explanatory (predictor) variable in this context? A. Weight B. Fuel efficiency
Mathematics
1 answer:
Maksim231197 [3]3 years ago
4 0

Answer:

Correct option: A. Weight.

Step-by-step explanation:

In regression analysis there are two kinds of variables: Explanatory and Response variable.

The explanatory variable are used to predict the changes in the response variable. They are also known as independent or predictor variable.

The response variable are observed for any changes caused by the explanatory variable. They are also known as the dependent or experimental variable.

In this case it is provided that heavier cars have lower fuel efficiencies.

It implies that there is linear inverse relationship between the variables weight of the car and fuel efficiency.

The response variable is the fuel efficiency and the explanatory variable is the weight of the car. Since the weight of the car is used to determine the fuel efficiency.

Thus, the explanatory variable is the weight of the car.

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How many fluid ounces in 8 ounces and 5 cups?
xenn [34]
<span>48 fluid ounces is the right answer</span>
3 0
3 years ago
What would the answer be
Hoochie [10]

Answer:

B.

Step-by-step explanation:

process of elimination. the red dot is not a 1/4 of the number of lines, so it cant be 12.25, 13.625 is impossible because it has a value less than 13, and 12.625 is impossible as well because it has a value less than 12.5 therefore 12.375 is the best answer, and the only correct answer

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7BW%7D%20%3D%202" id="TexFormula1" title="\sqrt[4]{W} = 2" alt="\sqrt[4]{W} = 2
solmaris [256]

Answer:

<h2>W = 16</h2>

Step-by-step explanation:

<h3>\sqrt[4]{W}  = 2 </h3>

To find W raise each of the sides of the equation to the power 4 to make W stand alone

That's

<h3>( { \sqrt[4]{W} })^{4}  =  {2}^{4}</h3>

We have

W = 2⁴

We have the final answer as

<h3>W = 16</h3>

Hope this helps you

6 0
3 years ago
Which statement correctly identifies a local minimum of the graphed function? Over the interval [–3, –2], the local minimum is 0
marta [7]

Answer:

C.

Step-by-step explanation:

As we can see on the graph C is our answer.

4 0
3 years ago
How would I find a? What formula would I use?
xenn [34]

Answer:

  You can use either of the following to find "a":

  • Pythagorean theorem
  • Law of Cosines

Step-by-step explanation:

It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.

I find it reasonably convenient to find the length of x using the sine of the 70° angle:

  x = (15 ft)/sin(70°)

  x ≈ 15.96 ft

That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.

__

Consider the diagram below. The relation between DE and AE can be written as ...

  DE/AE = tan(70°)

  AE = DE/tan(70°) = DE·tan(20°)

  AE = 15·tan(20°) ≈ 5.459554

Then the length EC is ...

  EC = AC - AE

  EC = 6.3 - DE·tan(20°) ≈ 0.840446

Now, we can find DC using the Pythagorean theorem:

  DC² = DE² + EC²

  DC = √(15² +0.840446²) ≈ 15.023527

  a ≈ 15.02 ft

_____

You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)

  DC² = AD² + AC² - 2·AD·AC·cos(A)

  a² = x² +6.3² -2·6.3x·cos(70°) ≈ 225.70635

  a = √225.70635 ≈ 15.0235 . . . feet

3 0
2 years ago
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