<span>48 fluid ounces is the right answer</span>
Answer:
B.
Step-by-step explanation:
process of elimination. the red dot is not a 1/4 of the number of lines, so it cant be 12.25, 13.625 is impossible because it has a value less than 13, and 12.625 is impossible as well because it has a value less than 12.5 therefore 12.375 is the best answer, and the only correct answer
Answer:
<h2>W = 16</h2>
Step-by-step explanation:
<h3>
![\sqrt[4]{W} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7BW%7D%20%20%3D%202)
</h3>
To find W raise each of the sides of the equation to the power 4 to make W stand alone
That's
<h3>
![( { \sqrt[4]{W} })^{4} = {2}^{4}](https://tex.z-dn.net/?f=%28%20%7B%20%5Csqrt%5B4%5D%7BW%7D%20%7D%29%5E%7B4%7D%20%20%3D%20%20%7B2%7D%5E%7B4%7D%20)
</h3>
We have
W = 2⁴
We have the final answer as
<h3>W = 16</h3>
Hope this helps you
Answer:
C.
Step-by-step explanation:
As we can see on the graph C is our answer.
Answer:
You can use either of the following to find "a":
- Pythagorean theorem
- Law of Cosines
Step-by-step explanation:
It looks like you have an isosceles trapezoid with one base 12.6 ft and a height of 15 ft.
I find it reasonably convenient to find the length of x using the sine of the 70° angle:
x = (15 ft)/sin(70°)
x ≈ 15.96 ft
That is not what you asked, but this value is sufficiently different from what is marked on your diagram, that I thought it might be helpful.
__
Consider the diagram below. The relation between DE and AE can be written as ...
DE/AE = tan(70°)
AE = DE/tan(70°) = DE·tan(20°)
AE = 15·tan(20°) ≈ 5.459554
Then the length EC is ...
EC = AC - AE
EC = 6.3 - DE·tan(20°) ≈ 0.840446
Now, we can find DC using the Pythagorean theorem:
DC² = DE² + EC²
DC = √(15² +0.840446²) ≈ 15.023527
a ≈ 15.02 ft
_____
You can also make use of the Law of Cosines and the lengths x=AD and AC to find "a". (Do not round intermediate values from calculations.)
DC² = AD² + AC² - 2·AD·AC·cos(A)
a² = x² +6.3² -2·6.3x·cos(70°) ≈ 225.70635
a = √225.70635 ≈ 15.0235 . . . feet