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1 year ago

Complete the table to show the steps for combining like terms.

Mathematics

1 answer:

Damm [24]1 year ago

6 0

The simplified form of the expression is 8.3y + 3.1

<h3>Equations and expressions</h3>

Given the following equations

(8-0.2+0.5)y + (2.2+1.3 - 0.4)

First is to Reorder the expression to have:

(8+0.5-0.2)y + (2.2+1.3 - 0.4)

Group the resulting expression

[8.5-0.2]y + (3.5 - 0.4)

Simplify the result

8.3y + 3.1

Hence the simplified form of the expression is 8.3y + 3.1

Learn more on factoring here: brainly.com/question/24734894

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1 and 2 pls help me with these math problems.........

jeka57 [31]

1. y=4x

2. (I am not able to graph it, but here are some points on the line.)
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3 years ago

138.4divided by16 show works it possible to show your work

Lorico [155]

Ok done. Thank to me :>

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2 years ago

If x = a sin α, cos β, y = b sin α.sin β and z = c cos α then (x²/a²) + (y²/b²) + (z²/c²) = ?

Oduvanchick [21]

$\large\underline{\sf{Solution-}}$

<u>Given:</u>

$\rm \longmapsto x = a \sin \alpha \cos \beta$

$\rm \longmapsto y = b \sin \alpha \sin \beta$

$\rm \longmapsto z = c\cos \alpha$

Therefore:

$\rm \longmapsto \dfrac{x}{a} = \sin \alpha \cos \beta$

$\rm \longmapsto \dfrac{y}{b} = \sin \alpha \sin \beta$

$\rm \longmapsto \dfrac{z}{c} = \cos \alpha$

Now:

$\rm = \dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} }$

$\rm = { \sin}^{2} \alpha \cos^{2} \beta + { \sin}^{2} \alpha \sin^{2} \beta + { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha (\cos^{2} \beta + \sin^{2} \beta )+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha \cdot1+ { \cos}^{2} \alpha$

$\rm = { \sin}^{2} \alpha + { \cos}^{2} \alpha$

$\rm = 1$

<u>Therefore:</u>

$\rm \longmapsto\dfrac{ {x}^{2} }{ {a}^{2}} + \dfrac{ {y}^{2} }{ {b}^{2} } + \dfrac{ {z}^{2} }{ {c}^{2} } = 1$

5 0

2 years ago

12/15,3/4,3/12 as a decimal/ how to get the answer

Darya [45]

Your answer is C I’m sure about that!

6 0

3 years ago

Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the temperature is 45 degrees at midnig

Nady [450]

Answer:

$D = 45+19*sin(\frac{\pi}{12}*t)$

Step-by-step explanation:

The amplitude (A) and the mean (M) temperature are given by:

$A=\frac{64-26}{2}\\ A= 19\\M=\frac{64+26}{2}\\ M= 45\\$

The mean temperature, 45 degrees. occurs at midnight (t=0) and the frequency is f=24h. Therefore, the temperature D, in degrees, as a function of t, in hours, is:

$D = M+A*sin(\frac{2\pi}{24}*t)\\D = 45+19*sin(\frac{\pi}{12}*t)$

5 0

3 years ago