An exponential decay function, and use it to approximate the population in 2027 is P(t) = 4001e^-(0.0037)(28) = P(t) = 4001e^-0.1036
<h3>Exponential equation</h3>
The standard exponential function is expressed as:
P(t) = P0e^-rt
- P0 is the initial population = 4001
- r is the rate. = 0.37% = 0.0037
- t is the time
Substitute
P(t) = 4001e^-(0.0037)t
If t = 28 (by 2027)
An exponential decay function, and use it to approximate the population in 2027 is P(t) = 4001e^-(0.0037)(28) = P(t) = 4001e^-0.1036
Learn more on exponential function here: brainly.com/question/12940982
#SPJ1
<span>4x(x) + 3(2x) and 4x2 + 6x => 4x^2 + 6x and 4x^2 + 6x
5(3x) - 4(3x) and 3x => 15x-12x=3x and 3x
4(3a) - 2(4a) and 4a2 => 12a-8a=4a and 4a^2
3(3a) + a(3a) and 3a2 + 9a => 9a+3a^2 and 9a + 3a^2
Can you spot the one which is different?
</span>
Answer:
D
Step-by-step explanation:
6.8 = (6/5)^x
6.8 = 1.2^x
x ln 1.2 = ln 6.8
x = ln 6.8 / ln 1.2
= 10.513966
fuol next time put the paraghpt too pls
Step-by-step explanation:
Answer:
R- (-10, -3)
S- (-10, -6)
Q- (-5, -3)
P- (-5, -6)
Step-by-step explanation:
Well, Q and P would be the exact same coordinates since that land directly on the reflection line.
Basically, on this graph/question you can count how far away the vertices is from the reflection line.
For example, Point R is 5 units away from the reflection line, therefore I need to count over 5 times to the left from the reflection line for point R. (Idk if that makes sense or not, ask questions if you are confused).
