1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
elena55 [62]
3 years ago
7

Frorn first to last, when did the presidents serve?

Mathematics
1 answer:
navik [9.2K]3 years ago
8 0

Step-by-step explanation:

you got this i believe in you

You might be interested in
if an external point of a circle is at a distance equal to the diameter of the circle from the center of the circle, the length
jeka57 [31]

Let the radius of the circle be r. Then the line from the external point through the center of the circle which extends to the far point on the circle has length 3r .By the tangent - secant theorem

t^2 = 3r * r = 3r^2 ( where t is the length of the tangent).

So t = √(3r^2) = √3r answer.

7 0
3 years ago
Dr. Jon planned to reward his class with candy because everyone got a A on the test. He surveyed every 4th student that entered
USPshnik [31]
This is an example of a systematic sample.

Dr. Jon developed a system in order to get a random sample. His plan was to survey the 4th student that entered his classroom.
8 0
3 years ago
Can someone help me find the volume and the surface area of this shape.​
mash [69]

Answer:

Got my points deducted by a loser name PoeticAesthetics

Step-by-step explanation:

5 0
2 years ago
Use series to verify that<br><br> <img src="https://tex.z-dn.net/?f=y%3De%5E%7Bx%7D" id="TexFormula1" title="y=e^{x}" alt="y=e^{
SVETLANKA909090 [29]

y = e^x\\\\\displaystyle y = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y= 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \frac{d}{dx}\left( 1+x+\frac{x^2}{2!} + \frac{x^3}{3!}+\frac{x^4}{4!}+\ldots\right)\\\\

\displaystyle y' = \frac{d}{dx}\left(1\right)+\frac{d}{dx}\left(x\right)+\frac{d}{dx}\left(\frac{x^2}{2!}\right) + \frac{d}{dx}\left(\frac{x^3}{3!}\right) + \frac{d}{dx}\left(\frac{x^4}{4!}\right)+\ldots\\\\\displaystyle y' = 0+1+\frac{2x^1}{2*1} + \frac{3x^2}{3*2!} + \frac{4x^3}{4*3!}+\ldots\\\\\displaystyle y' = 1 + x + \frac{x^2}{2!}+ \frac{x^3}{3!}+\ldots\\\\\displaystyle y' = \sum_{k=1}^{\infty}\frac{x^k}{k!}\\\\\displaystyle y' = e^{x}\\\\

This shows that y' = y is true when y = e^x

-----------------------

  • Note 1: A more general solution is y = Ce^x for some constant C.
  • Note 2: It might be tempting to say the general solution is y = e^x+C, but that is not the case because y = e^x+C \to y' = e^x+0 = e^x and we can see that y' = y would only be true for C = 0, so that is why y = e^x+C does not work.
6 0
3 years ago
Ramapo College has a total of 25,000 students enrolling this year. 42% of
salantis [7]

Answer: im sorry im not sure but you can find the answer if you look it up

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Other questions:
  • What is the product of 0.4 and 2.5
    15·2 answers
  • The table shows the cost in dollars, y, for renting a pair of snow skis or renting a snowboard for x days. Which function shows
    5·2 answers
  • Which of the following pair of polygons are NOT similar and why
    11·1 answer
  • The graph represents the heights of two climbers on a climbing wall over a 12-minute time period.
    11·2 answers
  • A movie theater is located on a map of a city represented by a coordinate plane. The location of the movie theater is at (−4, 2)
    8·1 answer
  • Explain how to solve the equation x divided by 9 =14
    13·1 answer
  • Find the differential equation of this function and indicate the order y = e^3x (acos3x +bsin3x)​
    8·1 answer
  • PLeaseeeeee HELPPPPPPP PLEASEEEE IM BEGGING SOMONE PLEASEEEEE HELPPPPPPPPPPPP PLEASEEEEEE​
    7·1 answer
  • Please help me <br> (both images are together)
    11·2 answers
  • Which intervals show f(x) decreasing? Check all that apply.
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!