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2 years ago

Quadrilateral FGHI is similar to quadrilateral JKLM. Find the measure of side JK

Mathematics

1 answer:

Stells [14]2 years ago

6 0

Answer:

Heyyyy!!

The answer is 66.9

please read the explanation... it will help... I promise

Step-by-step explanation:

Okay... Here we go...

The context mentions that the two quadrilaterals are similar... meaning their sides are proportional...

So... you basically have to find the scale factor...

(the math itself is easier than the explanation...

51/16 = 3.1875 (that is the number we multiplied the sides of quadrilateral FGHI to get quadrilateral JKLM...

so to get side JK all you have to do is multiply that scale factor by side FG... which after the use of a calculator results in 66.9 (i rounded, and used a calculator... lol)

but yeah... i hope this helps...

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Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of m

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Answer:Sorry i have no time to read it all bro

Step-by-step explanation:

4 0

3 years ago

Help with this exponential function!

butalik [34]

The population size after 6 years and after 8 years are 147 and 169 population respectively

<h3>Exponential functions</h3>

The standard exponential function is expressed as y = ab^x

where

a is the base

x is the exponent

Given the function that represents the population size P (t) of the species as shown;

$p(t)=\frac{550}{1+5e^{-0.1t}} \\$

For the population size after 6 years

$p(t)=\frac{550}{1+5e^{-0.1(6)}} \\P(6)=\frac{550}{3.744}\\ P(6)=147 population$

For the population after 8 years

$p(t)=\frac{550}{1+5e^{-0.1(8)}} \\P(8)=\frac{550}{3.2466}\\ P(8)=169 population$

Hence the population size after 6 years and after 8 years are 147 and 169 population respectively

Learn more on exponential function here: brainly.com/question/2456547

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7 0

2 years ago

A printer toner company launches a new product. The number of pages that this new toner can print is normally distributed with a

Vitek1552 [10]

Answer:

Step-by-step explanation:

Since the number of pages that this new toner can print is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = the number of pages.

µ = mean

σ = standard deviation

From the information given,

µ = 2300 pages

σ = 150 pages

the probability that this toner can print more than 2100 pages is expressed as

P(x > 2100) = 1 - P(x ≤ 2100)

For x = 2100,

z = (2100 - 2300)/150 = - 1.33

Looking at the normal distribution table, the probability corresponding to the z score is 0.092

P(x > 2100) = 1 - 0.092 = 0.908

2) P(x < 2200)

z = (x - µ)/σ/√n

n = 10

z = (2200 - 2300)/150/√10

z = - 100/47.43 = - 2.12

Looking at the normal distribution table, the probability corresponding to the z score is 0.017

P(x < 2200) = 0.017

3) for underperforming toners, the z score corresponding to the probability value of 3%(0.03) is

- 1.88

Therefore,

- 1.88 = (x - 2300)/150

150 × - 1.88 = x - 2300

- 288 = x - 2300

x = - 288 + 2300

x = 2018

The threshold should be

x < 2018 pages

4 0

3 years ago

What is the negative reciprocal of 2

Zinaida [17]

Answer:

- $\frac{1}{2}$

Step-by-step explanation:

The reciprocal of a number n is $\frac{1}{n}$

The negative reciprocal is the negative of this, thus

reciprocal of 2 is - $\frac{1}{2}$

3 0

3 years ago

According to industry sources, online banking is expected to take off in the near future. The projected number of households (in

Airida [17]

Answer:

(a) The least-square regression line is: $y=4.662+2.709x$ .

(b) The number of households using online banking at the beginning of 2007 is 31.8.

Step-by-step explanation:

The general form of a least square regression line is:

$y=\alpha +\beta x$

Here,

y = dependent variable

x = independent variable

α = intercept

β = slope

(a)

The formula to compute intercept and slope is:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} \end{aligned}$

The values of ∑X, ∑Y, ∑XY and ∑X² are computed in the table below.

Compute the value of intercept and slope as follows:

$\begin{aligned} \alpha &= \frac{\sum{Y} \cdot \sum{X^2} - \sum{X} \cdot \sum{XY} }{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 68.6 \cdot 55 - 15 \cdot 218.9}{ 6 \cdot 55 - 15^2} \approx 4.662 \\ \\\beta &= \frac{ n \cdot \sum{XY} - \sum{X} \cdot \sum{Y}}{n \cdot \sum{X^2} - \left(\sum{X}\right)^2} = \frac{ 6 \cdot 218.9 - 15 \cdot 68.6 }{ 6 \cdot 55 - \left( 15 \right)^2} \approx 2.709\end{aligned}$

The least-square regression line is:

$y=4.662+2.709x$

(b)

For the year 2007 the value of x is 10.

Compute the value of y for x = 10 as follows:

$y=4.662+2.709x$

$=4.662+(2.709\times10)\\=4.662+27.09\\=31.752\\\approx 31.8$

Thus, the number of households using online banking at the beginning of 2007 is 31.8.

5 0

2 years ago