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2 years ago

CAN SOMEONE SHOW ME STEP BY STEP?!?

Mathematics

1 answer:

My name is Ann [436]2 years ago

8 0

So first let’s multiply both sides by 10
Now we are left with this:
-4x-90<9

Now you want to move the -90 to the other side and when you do this you have to change the sign as well so now you have this:
-4x<9+90

Now add 9 and 90 together and you’ll get this:
-4x<99

Then divide both sides by -4 and flip the inequality sign

x>- 99/4

Your answer would be:

x>- 99/4

Hope this helps! :3

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When traveling to work, Cherise averages 60 miles per hour.Because of heavy traffic in the evening, she averages only 40 miles p

Slav-nsk [51]

<h3>Answer: 40 minutes</h3>

============================================================

Explanation:

The distance traveled is d = 80 miles.

When going to work, her speed is r = 60 mph. She takes t = d/r = 80/60 = 4/3 hours which converts to 80 minutes. Multiply by 60 to go from hours to minutes.

Notice how the '80' shows up twice (in "80 miles" and "80 minutes"). This is because traveling 60 mph is the same as traveling 1 mile per minute.

-----------------

Now as she's coming home, her speed becomes r = 40 and she takes t = d/r = 80/40 = 2 hours = 120 minutes.

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$\frac{\sin B}{b}=\frac{\sin A}{a} \\ \\ \sin B=\frac{b \sin A}{a} \\ \\ \sin B=\frac{13 \sin 29^{\circ}}{7.2} \\ \\ \boxed{m\angle B =\arcsin \left(\frac{65\sin 29^{\circ}{36} \right), 180^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$

Considering the diagram. $\angle B$ is shown to be acute, so $\boxed{m\angle B=\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)}$ .

Angles in a triangle add to 180°, so $m\angle C= 151^{\circ}-\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right)$ .

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$AB=\sqrt{13^2 + 7.2^2-2(13)(7.2)\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)} \\ \\ \boxed{AB=\sqrt{220.84-187.2\cos \left(\arcsin \left(\frac{65\sin 29^{\circ}}{36} \right) \right)}}$

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