Answer:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
Of the 2809 people who responded to survey, 1634 stated that they currently use social media.
This means that 
98% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The lower limit of this interval is:
The upper limit of this interval is:
The 98% confidence interval estimate of the proportion of adults who use social media is (0.56, 0.6034).
Answer:
1 2/21
Step-by-step explanation:
2/3 + 3/7
14/21+ 9/21= 23/21
Answer:
this isnt a math question
Step-by-step explanation:
;/
Answer:
C. Mrs. Alvarez's scores were less spread out than Mr. Crawford's scores.
Step-by-step explanation:
Mean Absolute Deviation is one of the Statistical measures which we can you to determine the variation that exist amongst a given set of data
Mean Absolute Deviation can be defined as how far or the distance between one set of data to another set of data.
The smaller the Mean Standard Deviation, the lower the degree of variation in the set of data. The data is less spread out
The larger the Mean Standard Deviation, the higher the degree of variation in the set of data. The data is Largely spread out
We are told in the question that:
Mrs. Alvarez's scores had a lower mean absolute deviation than Mr. Crawford's scores. Our conclusion would be that Mrs. Alvarez's scores were less spread out than Mr. Crawford's scores.
Option 2 is correct.
