Answer:
9
Step-by-step explanation:
a^2 + b^2 = h^2
15^2= 12^2 + b^2
225=144+b^2
81=b^2
9
Answer:
a real number
Step-by-step explanation: You didn't list the choices- a real number is all positive numbers except 0
Let's find the discriminant of <span>x^2+9x+14=0. Here, a=1, b=9 and c=14.
The discriminant is b^2-4ac. Substituting the above numeric values,
9^2-4(1)(14) = 81-56 = 25
The sqrt of 25 is 5. Thus, your polynomial has two unequal, real roots.
Off the point example: If the discriminant were zero, your poly would have two real, equal roots.</span>
Answer:
The diameter is 22.92 inches
Step-by-step explanation:
Hello, I can help you with this question
in this case we know the circumference of a circle, and we need to find out the diameter.
let's remember
the radius of a circle can be defined as

also

Step1
replace the value of the circumference of tyler's bike in equation 2 and isolate radius to find radius

Step 2
now, replace the value of radius into equation 1 to find diameter
radius=11.46 in

so, the diameter is 22.92 inches
I really hope it helps, have a great day.
Mid term :
Q1 = (88 + 85)/2 = 86.5
Q2 = (92 + 95)/2 = 93.5
Q3 = 100
IQR = Q3 - Q1 = 100 - 86.5 = 13.5
final exams :
Q1 = (65 + 78)/2 = 71.5
Q2 = (88 + 82)/2 = 85
Q3 = (95 + 93)/2 = 94
IQR = Q3 - Q1 = 94 - 71.5 = 22.5
so the final exams has the largest IQR