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2 years ago

Which of the following can be the third side of a triangle whose other two sides measure 8 inches and 10 inches

Mathematics

1 answer:

cupoosta [38]2 years ago

5 0

It has to be A. Hope that helps.

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Find vale of x ASSAP

Blizzard [7]

Answer:

x = 127°

Step-by-step explanation:

in each triangle, the value of each exterior angle is equal to the sum of its two non-adjacent interior angles..

47° + 80° = 127°

the third angle in the triangle:

180° - (47° + 80°) = 53°

exterior angle:

180° - 53° = 127°

7 0

3 years ago

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Translate the sentence into<br> an inequality <br><br> The product of b and 3 is at least -22

Sedaia [141]

Answer:

$3b \geq -22$

Step-by-step explanation:

Product of of 3 and b is 3b

At least means greater than or equal too.

$3b \geq -22$

3 0

2 years ago

Fraction written problems<br> 6th grade

Sholpan [36]

Answer:

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Step-by-step explanation:

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3 years ago

Which are the solutions of x2 = –7x – 8?

vovangra [49]

Answer:

The solutions are:

$x_1=\frac{-7+\sqrt{17}}{2}$ $x_2=\frac{-7-\sqrt{17}}{2}$

Step-by-step explanation:

We have the following quadratic equation

$x^2 = -7x - 8$

We can rewrite the equation as follows

$x^2+7x + 8=0$

Now we use the quadratic formula to solve the equation

For an equation of the form $ax ^ 2 + bx + c = 0$ the quadratic formula is:

$x=\frac{-b\±\sqrt{b^2-4ac}}{2a}$

In this case:

$a=1,\ b=7,\ c=8$

Then:

$x=\frac{-7\±\sqrt{7^2-4(1)(8)}}{2(1)}$

$x=\frac{-7\±\sqrt{49-32}}{2}$

$x=\frac{-7\±\sqrt{17}}{2}$

$x_1=\frac{-7+\sqrt{17}}{2}$

$x_2=\frac{-7-\sqrt{17}}{2}$

7 0

3 years ago

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21-x=13 telllllllllll mee

BaLLatris [955]

Answer:

$x = 8$

Step-by-step explanation:

$21-x=13 \\ x = 21 - 13 \\ x = 8$

4 0

3 years ago

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