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san4es73 [151]
2 years ago
11

NO LINKS!!!Please help me with these ​

Mathematics
1 answer:
german2 years ago
7 0

Answer:

\textsf{If }\: X \sim\textsf{N}(\mu,\sigma^2)\:\textsf{ then }\: \dfrac{X-\mu}{\sigma}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)

Therefore,

\textsf{If }\: X \sim \textsf{N}(33,4^2)\:\textsf{ then }\: \dfrac{X-33}{4}=Z, \quad \textsf{where }\: Z \sim \textsf{N}(0,1)

X=29 \implies Z=\dfrac{29-33}{4} \implies Z= -1

X=41 \implies Z=\dfrac{41-33}{4} \implies Z=2

X=25 \implies Z=\dfrac{25-33}{4} \implies Z=-2

No given lifespan is unusual, as they are all within 3 standard deviations of the mean.

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avanturin [10]
So the first thing you would have to is to find a common denominator so a common denominator between 11 and 15 is 165. 3/11 * 15 =45/165  next you would do 7/15 * 11=77/165 no that both denominators are the same we add the numerator but the denominator stays the same so 45/165 + 77/165 = 122/165
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hope this helps :)

5 0
2 years ago
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user100 [1]

Answer:

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2 years ago
Anyone know the answer to this?
kiruha [24]

Answer:

42

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6 0
3 years ago
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