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fiasKO [112]
2 years ago
15

Evaluate A) 3 B) 2 C) 5 D) 0

Mathematics
1 answer:
n200080 [17]2 years ago
3 0

Answer:

b)2

Step-by-step explanation:

2x2x2x2=16

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What is 58,413,000,000 in scientific notations
blagie [28]

Answer:

5.8413 × 10^10

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
If the current in a circuit is 2 +j2 amps and the resistance is 3-j2 ohms, what is the voltage
victus00 [196]

Answer:

The voltage is 10 + 2j volts.

Step-by-step explanation:

Ohm's first law:

By Ohm's first law, the voltage is the multiplication of the current by the resistance, that is:

V = R*i

The voltage is measured in Volts, the current in amps and the resistance in ohms.

In this question:

Both the current and the resistance have complex parts. We have to know that:

j^{2} = -1

We have that:

R = 3 - 2j, i = 2 + 2j

Then

V = R*i

V = (3 - 2j)*(2 + 2j)

V = 6 + 6j - 4j - 4j^{2}

V = 6 + 2j - 4(-1)

V = 10 + 2j

The voltage is 10 + 2j volts.

4 0
3 years ago
∠ A and ∠ B are complementary. If m∠ B = 80°, what is the measure of ∠ A?
Stolb23 [73]
Angle A would be 10 degrees.
Complementary angles add to 90 degrees.
So 90-80=10
6 0
3 years ago
A researcher compares two compounds (1 and 2) used in the manufacture of car tires that are designed to reduce braking distances
wariber [46]

Answer:

Step-by-step explanation:

Hello!

The objective of this experiment is to compare two compounds, designed to reduce braking distance, used in tire manufacturing to prove if the braking distance of SUV's equipped with tires made with compound 1 is shorter than the braking distance of SUV's equipped with tires made with compound 2.

So you have 2 independent populations, SUV's equipped with tires made using compound 1 and SUV's equipped with tires made using compound 2.

Two samples of 81 braking tests are made and the braking distance was measured each time, the study variables are determined as:

X₁: Braking distance of an SUV equipped with tires made with compound one.

Its sample mean is X[bar]₁= 69 feet

And the Standard deviation S₁= 10.4 feet

X₂: Braking distance of an SUV equipped with tires made with compound two.

Its sample mean is X[bar]₂= 71 feet

And the Standard deviation S₂= 7.6 feet

We don't have any information on the distribution of the study variables, nor the sample data to test it, but since both sample sizes are large enough n₁ and n₂ ≥ 30 we can apply the central limit theorem and approximate the distribution of both variables sample means to normal.

The researcher's hypothesis, as mentioned before, is that the braking distance using compound one is less than the distance obtained using compound 2, symbolically: μ₁ < μ₂

The statistical hypotheses are:

H₀: μ₁ ≥ μ₂

H₁: μ₁ < μ₂

α: 0.05

The statistic to use to compare these two populations is a pooled Z test

Z= \frac{(X[bar]_1-X[bar]_2)-(Mu_1-Mu_2)}{\sqrt{\frac{S^2_1}{n_1} +\frac{S^2_2}{n_2} } }

Z ≈ N(0;1)

Z_{H_0}= \frac{69-71-0}{\sqrt{\frac{108.16}{81} +\frac{57.76}{81} } }= -1.397

The rejection region if this hypothesis test is one-tailed to the right, so you'll reject the null hypothesis to small values of the statistic. The critical value for this test is:

Z_{\alpha  } = Z_{0.05}= -1.648

Decision rule:

If Z_{H_0} > -1.648 , then you do not reject the null hypothesis.

If Z_{H_0} ≤ -1.648 , then you reject the null hypothesis.

Since the statistic value is greater than the critical value, the decision is to not reject the null hypothesis.

At a 5% significance level, you can conclude that the average braking distance of SUV's equipped with tires manufactured used compound 1 is greater than the average braking distance of SUV's equipped with tires manufactured used compound 2.

I hope you have a SUPER day!

4 0
3 years ago
You have fit a regression model with two regressors to a data set that has 20 observations. The total sum of squares is 1000 and
Llana [10]

Answer:

Hence the adjusted R-squared value for this model is 0.7205.

Step-by-step explanation:

Given n= sample size=20  

Total Sum of square (SST) =1000  

Model sum of square(SSR) =750  

Residual Sum of Square (SSE)=250  

The value of R ^2 for this model is,  

R^2 = \frac{SSR}{SST}  

R^2 = 750/1000 =0.75  

Adjusted R^2 :

Adjusted R^2 =1- \frac{(1-R^2)\times(n-1)}{(n-k-1)}

Where k= number of regressors in the model.

Adjusted R^2 =1-(19\times 0.25/((20-2-1)) = 0.7205

3 0
3 years ago
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