1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashcka [7]
1 year ago
7

Find the Pearson correlation coefficient R for the given point round any intermediate calculation to no less than six decimal pl

aces and round your final answer to three decimal places

Mathematics
1 answer:
ElenaW [278]1 year ago
7 0

SOLUTION

Given the question in the image, the following are the solution steps to answer the question.

STEP 1: Get the given data values

STEP 2: Write the formula for calculating the coefficient

STEP 3

: Calculate the correlation coefficient

Using the calculator,

Hence, the value of r is 0.791

You might be interested in
Who else hates homework
AlladinOne [14]

Answer:

samme

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
There are 3 types of gummy bears:
mr Goodwill [35]

Using proportions, it is found that it takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct(when both increase or both decrease) or inverse proportional(when one increases and the other decreases, or vice versa), can be built to find the desired measures in the problem, or equations to find these measures.

10 mini-bears weights to 12.1 grams, hence the weight of a mini-bear is of:

12.1/10 = 1.21 grams.

10 regular bears weights to 23.1 grams, hence the weight of a regular bear is of:

23.1/10 = 2.31 grams.

1 super bear weights to 2250 grams, hence the proportion between the <u>weight of a super bear and the weight of a mini-bear</u> is:

2250/1.21 = 1860.

The proportion between the <u>weight of a super bear and the weight of a regular bear</u> is:

2250/2.31 = 974.

The difference of proportions is given by:

1860 - 974 = 886.

It takes 886 more mini-bears than regular-bears to have the same weight as one super-bear.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

5 0
1 year ago
What is the number of acute obtuse and right angle of a rectangle
matrenka [14]
The number of a acute angle in a rectangle is 89 through 1 the obtuse angle in a rectangle is 91 through inf and a right angle of a rectangle is 90 degrees 
4 0
3 years ago
Find the product of <br><br><br><br> <img src="https://tex.z-dn.net/?f=8%284%5Csqrt%207-%5Csqrt18%29" id="TexFormula1" title="8(
Eduardwww [97]

Answer:

Distribute

Step-by-step explanation:

8*4sq7 and 8*sq of 18

6 0
2 years ago
Read 2 more answers
The weight of an object is affected by gravity. Something that weighs 1 pound on earth will weigh 1.08 times that weight on Satu
laila [671]

Answer:

2.7 lb

Step-by-step explanation:

2x1.08=2.16

1/2x1.08=0.54

   2.16

+  <u>0.54</u>

   2.70

2.70 = 2.7

5 0
3 years ago
Other questions:
  • Find the point, M, that divides segment AB into a ratio of 5:6 if A is at (0, 22) and B is at (11, 0). A) (5, 12) B) (5, 11) C)
    11·2 answers
  • Gas mileage actually varies slightly with the driving speed of a car​ (as well as with highway vs. city​ driving). Suppose your
    14·1 answer
  • What is the solution of <br> 6x-5y=34<br> and<br> 3x+2y=8
    9·1 answer
  • What is the value of the expression -5/8 ?
    5·1 answer
  • Find the area of the shaded region below.<br> 12 cm<br> &lt;<br> 8 cm<br> 3 cm<br> 5 cm
    11·1 answer
  • Write the ratio 5/36 as a fraction in simplest form.
    6·2 answers
  • GIVING OUT BRAINLIEST ANSWER HELP ME ASAP!!! pleaseeeee
    9·1 answer
  • Which expression is equivalent to (x4)^9
    13·1 answer
  • Find the measure of each angle.
    14·1 answer
  • Can like someone help me with O.o.O (order of operations)
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!