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Feliz [49]
4 years ago
5

Find the 15th term of the arithmetic sequence -5x+3−5x+3, -9x-2−9x−2, -13x-7,.......???

Mathematics
1 answer:
Anna35 [415]4 years ago
5 0

Answer:

- 61x - 67

Step-by-step explanation:

The n th term of an arithmetic sequence is

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

d = - 9x - 2 - (- 5x + 3)

  = - 9x - 2 + 5x - 3

  = - 4x - 5 and a₁ = - 5x + 3, thus

a_{15} = - 5x + 3 + 14(- 4x - 5) = - 5x + 3 - 56x - 70 = - 61x - 67

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Which algebraic expression is a difference with two terms?
arlik [135]

Answer:

B)

Step-by-step explanation:

6x - 9

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5 0
3 years ago
A central angle of a circle with radius 150 cm cuts off an arc of 200 cm. Find each measure in Exercises 4 and 5.
Harrizon [31]

Answer:

Part 1) The exact value of the arc length is

Part 2) The approximate value of the arc length is

Step-by-step explanation:

step 1

Find the circumference of the circle

The circumference of a circle is equal to

C=2\pi r

we have

r=5 in

substitute

C=2\pi (5)

C=10\pi in

step 2

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Remember that the circumference of a circle subtends a central angle of 360 degrees

by proportion

\frac{10\pi }{360}=\frac{x}{150}

x=10\pi *150/360

x=\frac{25}{6} \pi in

step 3

Find the approximate value of the arc length

To find the approximate value, assume

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substitute

<h3>\frac{25}{6}(3.14)=13.1 in</h3>

6 0
2 years ago
I need help to solve it
timama [110]
Notice that the two semicircles have a radius of 10/2=5 and that their area is simply the area of a complete circle with a radius of 5.  In the center you have a rectangle that is 10 by 8.  So the total area is:

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A≈158.53 which is:

A≈158.5 m^2 (to the nearest tenth of a m^2)
4 0
4 years ago
Read 2 more answers
Find the area of the trapezoid using the formula using the A=1/2h(b1+b2)
pentagon [3]

Answer:

<em><u>9</u></em>

Step-by-step explanation:

  1. <em>1</em><em>/</em><em>2</em><em> </em><em>bh </em><em>(</em><em>b1+</em><em>b2)</em>
  2. <em>Count </em><em>all </em><em>the </em><em>squares </em><em>for </em><em>the </em><em>base </em><em>(</em><em>6</em><em> </em><em>squares)</em>
  3. <em>Half </em><em>it </em><em>bc </em><em>1</em><em>/</em><em>2</em><em>b</em><em>h</em><em>,</em><em> </em><em>which </em><em>is </em><em>not </em><em>3</em><em>(</em><em>h)</em>
  4. <em>Now </em><em>count </em><em>the </em><em>amount </em><em>of </em><em>squares </em><em>to </em><em>the </em><em>top </em><em>of </em><em>it </em><em>from </em><em>the </em><em>bottom </em><em>(</em><em>3</em><em> </em><em>as </em><em>well</em><em>)</em>
  5. <em>Now </em><em>the </em><em>problem </em><em>is </em><em>3</em><em>(</em><em>3</em><em>)</em><em> </em><em>which </em><em>is </em><em>9</em><em>.</em>
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<em><u>Hope </u></em><em><u>this </u></em><em><u>helps!</u></em><em><u> </u></em><em><u>Comment</u></em><em><u> </u></em><em><u>on </u></em><em><u>it </u></em><em><u>if </u></em><em><u>you </u></em><em><u>need </u></em><em><u>more </u></em><em><u>explanation</u></em><em><u>!</u></em><em><u>:</u></em><em><u>)</u></em>

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