Answer jejdidiswjwnsndnwjasnen
So hmm the food C = 6p + 3q and the food D = 4.5p + 1.5q
now, if we check how much is the ratios of C/D for each component, then, mixture M = 144p + 60q, must contain the same ratio for each "p" and "q" component

so, if we divide the 144p by 4+3, or 7 even pieces, 4 must belong to food C and 3 to food D, retaining the ratio of 4/3
and we do the same for 60q, we divide it in 2+1 or 3 even pieces, but that one is very clear, 2 must belong to food C and 1 to food D, 60/3 is clear ends up with a ratio of 40 and 20
now the "p" part... ends up as

that's what I see it, as the ratio of 4/3 and 2/1 being retained in the mixture M
Answer:
<u>Answer</u><u>:</u><u> </u><u>D</u>
Step-by-step explanation:

open the brackets [ distributive property ]

collect like terms:

divide either sides by 5:

Answer
8+6 x 9/-9
Step-by-step explanation:
The x is a multipcation sign
the dash is a division sign.