num%2==1
The modulo operator (%) divides the left hand side by the right hand side and returns the remainder. When dividing an odd number by 2 there will always be a remainder of 1.
Using the knowledge in computational language in JAVA it is possible to write a code that the document object to display the current platform in a tag in the webpage
<h3>Writting the code in JAVA:</h3>
<em> <TABLE></em>
<em> <ROWS> </em>
<em> <TR> </em>
<em> <TD>Shady Grove</TD></em>
<em> <TD>Aeolian</TD> </em>
<em> </TR> </em>
<em> <TR></em>
<em> <TD>Over the River, Charlie</TD></em>
<em> <TD>Dorian</TD> </em>
<em> </TR> </em>
<em> </ROWS></em>
<em> </TABLE></em>
<em> </em>
<em />
See more about JAVA at brainly.com/question/12975450
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Answer:
B. All decommissioned magnetic storage devices are degaussed and physically destroyed in accordance with industry-standard practices.
Explanation:
Answer:
- def getCharacterForward(char, key):
- charList = "ABCDEFGHIJKLMNOPQRSTUVWXYZ"
-
- if(len(char) > 1):
- return None
- elif(not isinstance(key, int)):
- return -1
- else:
- index = charList.find(char)
- if(index + key <= 25):
- return charList[index + key]
- else:
- return charList[(index + key)% 26]
-
- print(getCharacterForward("C", 4))
- print(getCharacterForward("X", 4))
Explanation:
Firstly, define a charList that includes all uppercase alphabets (Line 2). We presume this program will only handle uppercase characters.
Follow the question requirement and define necessary input validation such as checking if the char is a single character (Line 4). We can do the validation by checking if the length of the char is more than 1, if so, this is not a single character and should return None (Line 5). Next, validate the key by using isinstance function to see if this is an integer. If this is not an integer return -1 (Line 6 - 7).
Otherwise, the program will proceed to find the index of char in the charList using find method (Line 9). Next, we can add the key to index and use the result value to get forwarded character from the charList and return it as output (Line 11).
However, we need to deal a situation that the char is found at close end of the charList and the forward key steps will be out of range of alphabet list. For example the char is X and the key is 4, the four steps forward will result in out of range error. To handle this situation, we can move the last two forward steps from the starting point of the charList. So X move forward 4 will become B. We can implement this logic by having index + key modulus by 26 (Line 13).
We can test the function will passing two sample set of arguments (Line 15 - 16) and we shall get the output as follows:
G
B
Answer:
A lookaside buffer translation (TLB) is a memory cache that reduces the time it takes to access a user memory place. TLB includes the most lately used page table entries.
TLB is used to overcome the issue of sizes at the time of paging. Page Table Entry (PTE) is used for framing the memory ,but it uses two references one for finding the frame number
and the other for the address specified by frame number.
<u>Formula for finding effective memory access time-</u>
Effective Memory Access Time = (TLB access_time+Memory Access Time)*hit ratio + (TLB access_time+2*Memory Access Time)*(miss ratio)
Given in question,
Hit ratio = 0.90
Memory Access Time = 150ns
TLB access time= 5ns
Effective Memory Access Time = (TLB access_time+Memory Access Time)*hit ratio + (TLB access_time+2*Memory Access Time)*(miss ratio)
=(5+150) * 0.90 + (5+2*150)*(1-0.90)
=155 * 0.90 + (305*0.1)
=139.5 + 30.5
= 170ns
cartesian coordinates for both the carries waves of the same wavelengths and represents the result in total.
