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Katyanochek1 [597]
2 years ago
11

If the length of a rectangle is 6 more than twice the width and the total perimeter is 84cm, what is the rectangle's length?

Mathematics
1 answer:
tino4ka555 [31]2 years ago
5 0

Step-by-step explanation:

length = 2×width + 6

84 = 2×length + 2×width

now using the first in the second equation :

84 = 2×(2×width + 6) + 2×width = 4×width + 12 + 2×width

84 = 6×width + 12

72 = 6×width

width = 12 cm

length = 2×width + 6 = 2×12 + 6 = 24 + 6 = 30 cm

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7 0
3 years ago
the width of a rectangular yard is 3 yards more than twice its length. the perimeter of the garden is 192 yards
Bas_tet [7]

Answer:

Step-by-step explanation:

W = 2L + 3, and:

P = 2W + 2L = 192

Substituting 2L + 3 for W, we get:

P = 2(2L + 3) + 2L = 192, or

4L + 6 + 2L = 192, or:

6L = 186

L = 186/6 = 31

The length is 31, the width is 62 + 3, or 65

Therefore, the perimeter P is P = 2(31) + 2(65) = 130 + 62  = 192 (OK!)

6 0
3 years ago
What is the exact volume of the cylinder?, (a) 54in. (b) 108in. (c) 162in. (d) 324in.
lbvjy [14]
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4 0
3 years ago
Let A = { 0 , 2 , 4 , 6 } , B = { 1 , 2 , 3 , 4 , 5 } , and C = { 1 , 3 , 5 , 7 } . Find { x ∣ x ∈ B or x ∈ C } .
EastWind [94]

Answer:

  {1, 2, 3, 4, 5, 7}

Step-by-step explanation:

x in B or C is ...

  B ∪ C = {1, 2, 3, 4, 5, 7}

5 0
3 years ago
X^2-18x=-72<br><br> I need two solutions. Thanks.
eimsori [14]

Hey Astute!

Solve: x^2 - 18x = -72

Solution:

x^2 − 18x − (−72) = −72 − (−72) (Subtract -72 from both sides of the equation)

x^2 − 18x + 72 = 0

(x − 6) (x − 12) = 0 (Factor left side)

x − 6 = 0 or x − 12 = 0 (factors have to equal 0)

6 - 6 = 0 or 12 - 12 = 0

Answer:

x = 6 or x = 12

Hope This Helps, Have a Great Day!

7 0
3 years ago
Read 2 more answers
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