Candice got a preloaded debit card for her birthday, and she finally knows what she wants to buy with it! She's going to buy a c
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We use trigonometry because we know an angle and a side length.
We are looking for one of the sides that isn't the hypotenuse:
As illustrated by the picture I made below:
We know both unknown angles will be 45 degrees, as there are 180 degrees in a triangle, we know the triangle is a right angle triangle (has 90 degrees) so, (180-90)/2 = 45
Using SOH CAH TOA, short for : SIN- OH COS- AH TAN- OA
We are looking for the one with H, as we know what H is.
I am picking "SIN- OH", but we could use "COS- AH"
The formula for this is: Sin(angle) = O/H
<u /><u>We substitute the angle (45) and the length for H (16)
</u>
Sin(45)= O/16 <- rearrange it
Sin(45)*16= O <- Solve in the calculator
13.6145 (4 DP)= O
The legs = O
The legs have a length of "13.6145 (4 DP)" each
We are looking for one of the sides that isn't the hypotenuse:
As illustrated by the picture I made below:
We know both unknown angles will be 45 degrees, as there are 180 degrees in a triangle, we know the triangle is a right angle triangle (has 90 degrees) so, (180-90)/2 = 45
Using SOH CAH TOA, short for : SIN- OH COS- AH TAN- OA
We are looking for the one with H, as we know what H is.
I am picking "SIN- OH", but we could use "COS- AH"
The formula for this is: Sin(angle) = O/H
<u /><u>We substitute the angle (45) and the length for H (16)
</u>
Sin(45)= O/16 <- rearrange it
Sin(45)*16= O <- Solve in the calculator
13.6145 (4 DP)= O
The legs = O
The legs have a length of "13.6145 (4 DP)" each
Answer:
Mike is not right
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its surface areas is equal to the scale factor squared
Let
z----> the scale factor
x----> surface area of the enlarged rectangular prism
y-----> surface area of the original rectangular prism
so
In this problem we have
substitute
so
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism
therefore
Mike is not right
<em>Verify with an example</em>
we have a rectangular prism
The surface area of the prism is equal to
substitute the values
If he doubles each dimension of any rectangular prism
then
the new dimensions will be
The new surface area will be
therefore
The surface area of the enlarged rectangular prism is 4 times the surface area of the original rectangular prism