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Fiesta28 [93]
2 years ago
5

10a²+4= -186 Very easy quick points

Mathematics
1 answer:
OlgaM077 [116]2 years ago
5 0

Answer:

please see explanation

Step-by-step explanation:

10a {}^{2}  + 4 =  - 186 \\ 10a {}^{2}  =  - 186 - 4 \\ 10a {}^{2}  =  - 190 \\ divide \: bothsides \: by \: 10 \\  \frac{10a {}^{2} }{10}  =   \frac{ - 190}{10}  \\ a { }^{2}  =  - 19 \\ square \: root \: bothsides \\    \sqrt{a {}^{2} }  =    \sqrt{ - 19}   \\ a =  - 1 \sqrt{19 }  \\ a =   + i \sqrt{19}  \: or \: a =  - i \sqrt{19}

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Which of the following is an arithmetic sequence?
gladu [14]

Answer:

  A.  3, 0, -3, -6

Step-by-step explanation:

The sequence with constant first differences is an arithmetic sequence. The sequence of A has a common difference of -3, so is an arithmetic sequence.

6 0
3 years ago
Solve for k<br> k - 2/ 5 = 11j
Vikki [24]
You have to move the -2/5 by the 11j to get k by its self
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8 0
3 years ago
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Jack reads his book for 8 minutes before school and 10 minutes after school. He attends school Monday through Friday. Which equa
sweet-ann [11.9K]

Answer:

<h2>90 min or 1hr 30 mins</h2>

Step-by-step explanation:

Even though the options to choose from are not given in this question we can try and lay our hand on the most likely equation for the number of minutes Jack reads his book.

firstly on a daily Jack reads a total of = 8+10 = 18 mins

He attends school from Mon- fri = 5 days

Now on a weekly basis jack reads = 5*18

in other words, the equation is simply the number of days times the time spent to read his book per day

hence this is  = 90 min or 1hr 30 mins

5 0
3 years ago
If the mean weight of 4 backfield members on the football team is 221 lb and the mean weight of the 7 other players is 202 lb, w
MatroZZZ [7]

Let x_1, x_2, x_3, x_4, x_5, x_6, x_7, x_8, x_9, x_{10}, x_{11} be the weight of i-th player.

1. If the mean weight of 4 backfield members on the football team is 221 lb, then

\dfrac{x_1+x_2+x_3+x_4}{4}=221\ lb.

2. If the mean weight of the 7 other players is 202 lb, then

\dfrac{x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{7}=202\ lb.

3. From the previous statements you have that

x_1+x_2+x_3+x_4=221\cdot 4=884 \lb,\\ \\x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=202\cdot 7=1414\ lb.

Add these two equalities and then divide by 11:

x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}=884+1414=2298\ lb,\\ \\\dfrac{x_1+x_2+x_3+x_4+x_5+x_6+x_7+x_8+x_9+x_{10}+x_{11}}{11}=\dfrac{2298}{11}=208\dfrac{10}{11}\ lb.

Answer: the mean weight of the 11-person team is 208\dfrac{10}{11}\ lb.

4 0
3 years ago
In Mr. Hamilton's classroom, there are 16 supply boxes in the cabinet. Each supply box
gulaghasi [49]

Answer:

12

Step-by-step explanation:

192/16=12

5 0
3 years ago
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