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Effectus [21]
1 year ago
7

What is the product of (x − 3) and (x + 7)?

Mathematics
2 answers:
lidiya [134]1 year ago
5 0

              - - - - - - - - - - - - - - - - - - - - -- - - - - - - - - - - - - - - - - -

\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond

           What is the product of (x-3) and (x+7)?

\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond

          First multiply the x's:-

x•x=x²

Now multiply x times 7:-

7x

So we have

x²+7x

Now multiply -3 times x:-

-3x

So we have

x²+7x-3x

Now multiply 7 and -3:-

x²+7x-3x-21

On simplification,

x²+4x-21

<h3>Good luck.</h3>

            - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -

Alisiya [41]1 year ago
5 0
X times X +(-3) times X + X times 7 +(-3) times (7)=x^2 -3x +7x -21
= x ^2 +4x-21
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3 years ago
Subtract: 4x/x^2-25 - 2/x^2+2x-15
Alex777 [14]

Answer: \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

Step-by-step explanation:

Given

Subtract the expression

\Rightarrow \dfrac{4x}{x^2-25}-\dfrac{2}{x^2+2x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{x^2+5x-3x-15}\\\\\Rightarrow \dfrac{4x}{(x-5)(x+5)}-\dfrac{2}{(x+5)(x-3)}\\\\\text{Take the LCM and subtract}\\\\\Rightarrow \dfrac{4x(x-3)-2(x-5)}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-12x-2x+10}{(x-5)(x+5)(x-3)}\\\\\Rightarrow \dfrac{4x^2-14x+10}{(x-5)(x+5)(x-3)}

4 0
2 years ago
Hello can anyone check if my answer is correct
sleet_krkn [62]
The answer is not correct
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