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Natalija [7]
3 years ago
6

Which of the following equations represents a line that passes through the points​

Mathematics
1 answer:
Xelga [282]3 years ago
6 0

Answer:

C) I only

Step-by-step explanation:

( -1, -2) and (0,4)

Slope:

m=(y2-y1)/(x2-x1)

m=(4+2)/(0+1)

m=6/1

m=6

Slope-intercept:

y - y1 = m(x - x1)

y + 2 = 6(x + 1)

y + 2 = 6x + 6

y = 6x + 4

y - 16 = 6(x - 2)

y - 16 = 6x - 12

y = 6x + 4

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STatiana [176]

Answer:

K=2 that is the answer

6 0
3 years ago
Determine the value of x and the measure of each angle.
puteri [66]

Answer:

x=61; 125; 55

Step-by-step explanation:

2x+3+x-6=180

3x-3=180

3x=183

x=61

Angle 1=2x+3=2*61+3=125

Angle 2=61-6=55

8 0
3 years ago
A parabola can be drawn given a focus of (−6,−1) and a directrix of y=1. Write the equation of the parabola in any form.
kkurt [141]

Answer:

y = -(x + 6)²/4

Step-by-step explanation:

Since the equation of a parabola is given as the distance of a point to a given point(focus) being equal to the distance of the point fro a given line (directrix),

and our focus is at (-6,-1) and our directrix is y = 1, then by the distance equation, the distance from each point to the point (x, y) is

√[(x - x)² + (y - 1)²] = √[(x - (-6))² + (y - (-1))²]

√[0² + (y - 1)²] = √[(x + 6)² + (y + 1)²]

√(y² -2y + 1) = √[(x² + 12x + 36) + (y² + 2y + 1)]

squaring both sides, we have

y² - 2y + 1 = x² + 12x + 36 + y² + 2y + 1

collecting like terms, we have

y² - 2y - y² - 2y = x² + 12x + 36 + 1 - 1

simplifying, we have

- 4y = x² + 12x + 36

factorizing the expression in x, we have

-4y = (x + 6)²

y = -(x + 6)²/4

3 0
3 years ago
Rotate the figure shown 180° clockwise. Record the coordinates of the image.
Mariulka [41]

Answer:

where's the image?

Step-by-step explanation:

3 0
3 years ago
What is the missing constant term in the perfect square that starts with x2+10x
Art [367]

Answer:

+25

Step-by-step explanation:

(x+5)²=x²+10x+25

3 0
3 years ago
Read 2 more answers
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