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anastassius [24]
2 years ago
15

Answer the Question below Please

Mathematics
2 answers:
True [87]2 years ago
3 0
1/2 as 3 out of the 6 are checkered

Hope I helped!
vampirchik [111]2 years ago
3 0

Answer:

1/2 (one half) or 0.5

Step-by-step explanation:

Three is half of six, so the probability that it will be checkered is exactly one half. Lets say you have six papers in a hat, and you drew on three of them. In that scenario, you have one half chance of getting a paper you drew on.

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HURRY!!!!!!!!!!!!! 20PTS!!!! AND BRAINLIEST!!!!!!!!!!!!!!!!!!
Sedaia [141]

Answer:

Step-by-step explanation:

The roots of a function are the x-intercepts. By definition, the y-coordinate of points lying on the x-axis is zero. Therefore, to find the roots of a quadratic function, we set f (x) = 0, and solve the equation, ax2 + bx + c = 0.

6 0
3 years ago
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Solve the equation. –x – 7 = 16 –23 8 22 –9
Svetradugi [14.3K]

Answer:

x = - 23

Step-by-step explanation:

Given

- x - 7 = 16 ( Isolate - x by adding 7 to both sides )

- x = 23 ( multiply both sides by - 1 )

x = - 23

4 0
3 years ago
Surface integrals using an explicit description. Evaluate the surface integral \iint_{S}^{}f(x,y,z)dS using an explicit represen
Jobisdone [24]

Parameterize S by the vector function

\vec r(x,y)=x\,\vec\imath+y\,\vec\jmath+f(x,y)\,\vec k

so that the normal vector to S is given by

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=\left(\vec\imath+\dfrac{\partial f}{\partial x}\,\vec k\right)\times\left(\vec\jmath+\dfrac{\partial f}{\partial y}\,\vec k\right)=-\dfrac{\partial f}{\partial x}\vec\imath-\dfrac{\partial f}{\partial y}\vec\jmath+\vec k

with magnitude

\left\|\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}\right\|=\sqrt{\left(\dfrac{\partial f}{\partial x}\right)^2+\left(\dfrac{\partial f}{\partial y}\right)^2+1}

In this case, the normal vector is

\dfrac{\partial\vec r}{\partial x}\times\dfrac{\partial\vec r}{\partial y}=-\dfrac{\partial(8-x-2y)}{\partial x}\,\vec\imath-\dfrac{\partial(8-x-2y)}{\partial y}\,\vec\jmath+\vec k=\vec\imath+2\,\vec\jmath+\vec k

with magnitude \sqrt{1^2+2^2+1^2}=\sqrt6. The integral of f(x,y,z)=e^z over S is then

\displaystyle\iint_Se^z\,\mathrm d\Sigma=\sqrt6\iint_Te^{8-x-2y}\,\mathrm dy\,\mathrm dx

where T is the region in the x,y plane over which S is defined. In this case, it's the triangle in the plane z=0 which we can capture with 0\le x\le8 and 0\le y\le\frac{8-x}2, so that we have

\displaystyle\sqrt6\iint_Te^{8-x-2y}\,\mathrm dx\,\mathrm dy=\sqrt6\int_0^8\int_0^{(8-x)/2}e^{8-x-2y}\,\mathrm dy\,\mathrm dx=\boxed{\sqrt{\frac32}(e^8-9)}

5 0
3 years ago
What is the coefficient and constant of 3c + 4
kobusy [5.1K]

Answer:

The coefficient is 3 and the constant is 4 in

relation to the equation mx + c where m is the coefficient of x and c is the constant.

4 0
3 years ago
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The quotient of a number and -5 is 6. What is the number?
Fofino [41]

Answer:

-30.

Step-by-step explanation:

We are dividing by a negative number to get a positive one, so we need the other number to also be negative.

We can re-write this as -5 * 6

This can be simplified into -30.

7 0
3 years ago
Read 2 more answers
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