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seraphim [82]
2 years ago
10

Convert -450° from degrees to radians. (5 points)

Mathematics
1 answer:
ValentinkaMS [17]2 years ago
4 0
Negative five pi divided by two

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Approximate, in feet, the circumference of a circle with radius = 6 ft. (Round your answer to one decimal place.)
Viktor [21]

Answer:

37.7

Step-by-step explanation:

Circumference of circle =2pir

I took pi=3.14

C=2xpix6=37.7square ft

8 0
3 years ago
How would you go about finding the area and perimeter of a composite figure?
fgiga [73]

Explanation:

The area is the sum of the areas of the non-overlapping parts. The figure is called "composite" because it is composed of figures whose area formulas you know. Decompose the figure into those, find the area of each, then sum those areas to find the area of the whole.

<u>For example</u>

If the figure consists of a rectangle and semicircle, find the areas of each of those. Then add the areas together to find the total area.

__

Likewise, the perimeter of a composite figure will be the sum of the "exposed" perimeters of the parts. (Some edges of the figures making up the composition will be internal, so do not count toward the perimeter of the composite figure.)

<u>For example</u>

If the curved edge of the semicircle of the figure described in the example above is part of the perimeter, then its length will be half the circumference of a circle. If the straight edge of the semicircle is "internal" and not a part of the perimeter, its length (the diameter of the semicircle) may need to be partially or wholly subtracted from the perimeter of the rectangle, depending on the actual arrangement of the composite figure. In other words, add up the lengths of the edges that "show."

_____

<em>Additional comments</em>

In the above, we have described how to add the areas of parts of the figure. In some cases, it can be easier to identify a larger figure, or one that is more "complete", then subtract the areas of the parts that aren't there. For example, an L-shaped figure can be decomposed into two rectangles. Or it can be decomposed into a larger rectangle covering the entire outside dimensions, from which a smaller rectangle is subtracted to leave the L-shape. Depending on how dimensions are shown, one computation or the other may be easier.

Likewise, for the purposes of computing the perimeter, lines of the figure may be rearranged in any convenient way, as long as their total length doesn't change. The L-shape just described will have a perimeter exactly equal to the perimeter of the rectangle that encloses its outside dimensions, for example. You can see this if you move the two lines forming the concave edges.

Familiarity with area formulas can help with area. For example, you know that the area of a triangle is the same as that of a rectangle half the height. Likewise, the area of a trapezoid is the area of a rectangle with the same height and a width equal to the midline of the trapezoid.

5 0
3 years ago
Consider the system x' = rx + x3 - x5​, which exhibits a pitchfork bifurcation.
trapecia [35]

Answer:

rs = -3/16  and the three minima x₁, x ₂ and x₄ fall at  the value of integrating curve C

Step-by-step explanation:

The answer is found in the attachment.

5 0
3 years ago
Craig used repeated addition to show 3 times 3/5. Which shows an expression Craig could write?
guapka [62]
3/5+3/5+3/5=9/5=1 4/5
5 0
3 years ago
Read 2 more answers
5-2(4a+1)+3a=13 <br><br> A= 2/3<br> A= -2<br> A= -6/5<br> A=2
VMariaS [17]

Answer:

                   a = -2

Simplifying 5 + -2(4a + 1) + 3a = 13 Reorder the terms: 5 + -2(1 + 4a) + 3a = 13 5 + (1 * -2 + 4a * -2) + 3a = 13 5 + (-2 + -8a) + 3a = 13 Combine like terms: 5 + -2 = 3 3 + -8a + 3a = 13 Combine like terms: -8a + 3a = -5a 3 + -5a = 13 Solving 3 + -5a = 13 Solving for variable 'a'. Move all terms containing a to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -5a = 13 + -3 Combine like terms: 3 + -3 = 0 0 + -5a = 13 + -3 -5a = 13 + -3 Combine like terms: 13 + -3 = 10 -5a = 10 Divide each side by '-5'. a = -2

6 0
3 years ago
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