Answer:
answer is c of your question
Answer:
y > 1
Step-by-step explanation:
Answer:
23.44%
Step-by-step explanation:
The probability of getting a 4 on the first 2 throws and different numbers on the last 5 throws = 1/6 * 1/6 * (5/6)^5
= 0.01116
There are 7C2 ways of the 2 4's being in different positions
= 7*6 / 2 = 21 ways.
So the required probability = 0.01116 * 21
= 0.2344 or 23.44%.
Answer:
1. a =3(2a) +5 and a= 6a+5
2. 47=3(2times 7) +5 and 47 =6 time 7 plus 5
Step-by-step explanation:
Answer:327412000
Step-by-step explanation: