Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Step-by-step explanation:
Let x and y area the random variable that represents the heights of women and men.
Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.
i.e.

Since , 
Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).
[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.
i.e.

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).
[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Answer:
your is 5
Step-by-step explanation:
and make me barinly least
Answer:
C
Step-by-step explanation:
Answer:
The correct answer is A

Step-by-step explanation:
We want to determine the decimal equivalence of
.
We perform the long division as shown in the attachment.
Note that in carry out the long division, the denominator which is 3, will be outside the long division sign, while the numerator which is
, will be inside the long division sign.
We see that the quotient of our long division is
.
We can rewrite this as 
Therefore
.
They are up and down and left and right