The <em>vertex</em> form of the <em>quadratic</em> equation, written in <em>standard</em> form, f(x) = 2 · x² - 20 · x + 8 is f(x) + 75 = 2 · (x - 5)².
<h3>What is the vertex form of a quadratic equation?</h3>
In this problem we have a <em>quadratic</em> equation in <em>standard</em> form, whose form is defined by f(x) = a · x² + b · x + c, where a, b, c are <em>real</em> coefficients, and we need to transform it into <em>vertex</em> form, defined as:
f(x) - k = C · (x - h)² (1)
Where:
- (h, k) - Vertex coordinates
- C - Vertex constant
This latter form can be found by algebraic handling. If we know that f(x) = 2 · x² - 20 · x + 8, then its vertex form is:
f(x) = 2 · x² - 20 · x + 8
f(x) = 2 · (x² - 10 · x + 4)
f(x) + 2 · 25 = 2 · (x² - 10 · x + 25)
f(x) + 75 = 2 · (x - 5)²
The <em>vertex</em> form of the <em>quadratic</em> equation, written in <em>standard</em> form, f(x) = 2 · x² - 20 · x + 8 is f(x) + 75 = 2 · (x - 5)².
To learn more on quadratic equations: brainly.com/question/1863222
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For this case we have that by definition, the equation of a line of the point-slope form is given by:
Where:
m: It is the slope of the line
It is a point that belongs to the line
According to the data of the statement we have to:
Substituting in the equation we have:
Answer:
Answer:
Step-by-step explanation:
There is no solution
