There is not enough info to answer this question.
Answer:
18
Step-by-step explanation:
Answer:
7
Step-by-step explanation:
56 times (1/2)=28
Again times (1/2)=14
Last one times (1/2)=7
C(1)=56
C(2)=28
C(3)=14
C(4)=7
Answer:
C. ∆ABD ≅ ∆CBD by the SSS Postulate
Step-by-step explanation:
We can prove that ∆ABD and ∆CBD congruent by the SSS Postulate.
The SSS postulate states that of three sides in one triangle are congruent to three corresponding sides in another, therefore, the two triangles are congruent.
From the diagram shown,
AB ≅ CB,
AD ≅ CD
BD = BD
We have three sides in ∆ABD that are congruent to three corresponding sides in ∆CBD.
Therefore, ∆ABD ≅ ∆CBD by the SSS Postulate
Since 7 - 3 is in parentheses, I will subtract that first, giving me 4. Next, I divide 11 and 4. 11 / 4 = 2.75