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Vlada [557]
2 years ago
7

PLEASE HELP!! will give brainliest for the right answer.

Mathematics
1 answer:
Ludmilka [50]2 years ago
4 0

Answer:

bro what's the question and there  is no doc

Step-by-step explanation:

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Factor the expression. r^2 – 49 a. (r – 7)(r 9) b. (r 7)(r 7) c. (r – 7)(r 7) d. (r – 7)(r – 7)
gayaneshka [121]
r^2-49=r^2-7^2\\\\/use\ a^2-b^2=(a-b)(a+b)/\\\\=\boxed{(r-7)(r+7)}
6 0
3 years ago
What is a formula for the nth term of the given sequence?
lakkis [162]

Answer: option D is the correct answer.

Step-by-step explanation:

The given sequence is a geometric sequence because the consecutive terms differ by a common ratio.

The formula for determining the nth term of a geometric progression is expressed as

an = a1r^(n - 1)

Where

a1 represents the first term of the sequence.

r represents the common ratio.

n represents the number of terms.

From the information given,

a1 = 36

r = 12/36 = 4/12 = 1/3

Therefore, the formula for the nth term of the sequence is

an = 36 × 1/3^(n - 1)

an = 36 × 3^-1(n - 1)

an = 36 × 3^(-n + 1)

an = 36 × 3^(1 - n)

6 0
3 years ago
(1/3) a = -5 What does a equal?????????????????????????????????????????????????????
KiRa [710]

Answer:

minus 15

Step-by-step explanation:

times the bottom by the right hand side

6 0
2 years ago
A heavy rope, 50 ft long, weighs 0.6 lb/ft and hangs over the edge of a building 120 ft high. Approximate the required work by a
Anastasy [175]

Answer:

Exercise (a)

The work done in pulling the rope to the top of the building is 750 lb·ft

Exercise (b)

The work done in pulling half the rope to the top of the building is 562.5 lb·ft

Step-by-step explanation:

Exercise (a)

The given parameters of the rope are;

The length of the rope = 50 ft.

The weight of the rope = 0.6 lb/ft.

The height of the building = 120 ft.

We have;

The work done in pulling a piece of the upper portion, ΔW₁ is given as follows;

ΔW₁ = 0.6Δx·x

The work done for the second half, ΔW₂, is given as follows;

ΔW₂ = 0.6Δx·x + 25×0.6 × 25 =  0.6Δx·x + 375

The total work done, W = W₁ + W₂ = 0.6Δx·x + 0.6Δx·x + 375

∴ We have;

W = 2 \times \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= 2 \times \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 750

The work done in pulling the rope to the top of the building, W = 750 lb·ft

Exercise (b)

The work done in pulling half the rope is given by W₂ as follows;

W_2 =  \int\limits^{25}_0 {0.6 \cdot x} \, dx + 375= \left[0.6 \cdot \dfrac{x^2}{2} \right]^{25}_0 + 375 = 562.5

The work done in pulling half the rope, W₂ = 562.5 lb·ft

6 0
2 years ago
The graph shows a line and two similar triangles.
docker41 [41]

Answer:

y=1/3x+2

Step-by-step explanation:

7 0
2 years ago
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