ANSWER:
the conditions are the angle a is equal to angle c and ab = bc . Hence we need to prove that the triangles is congruent to the triangle cbe. ... angle A =angle C and AB=BC.
Answer:
The area is 31.5
Step-by-step explanation:
first you find the area of the rectangle (l x w) = 21
next you find the area of the triangle (b x h x 1/2) = 10.5
then you add the two areas together = 31.5
good luck with your khan academies :)
Answer:
Step-by-step explanation:
<u>Step 1: Convert words into numbers
</u>
<u>Step 2: Multiply
</u>
<u>Step 3: Divide
</u>
Answer:
Answer:
V ≈ 1847.26
Step-by-step explanation:
<u>Circular Cone Formulas in terms of radius r and height h:</u>
The volume of a cone:
V = (1/3)πr2h
Slant height of a cone:
s = √(r2 + h2)
Lateral surface area of a cone:
L = πrs = πr√(r2 + h2)
The base surface area of a cone (a circle):
B = πr2
The total surface area of a cone:
A = L + B = πrs + πr2 = πr(s + r) = πr(r + √(r2 + h2))
Therefore, the solution
V = πr 2h
/ 3 = π·142·9/ 3 ≈ 1847.25648
For the first one a = 2.5. For the second one m = 4. For the third one m = -4
