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Sladkaya [172]
3 years ago
12

Based on the graph, what is the dependent variable, the equation relating the two variables, and how far will the dragonfly trav

el in 24 hours if it continues to fly at the same speed?
The dependent variable is time, the equation is y = 22x, and the dragonfly will travel 528 miles.
The dependent variable is time, the equation is x = 22y, and the dragonfly will travel 1,056 miles.
The dependent variable is distance, the equation is y = 22x, and the dragonfly will travel 528 miles.
The dependent variable is distance, the equation is x = 22y, and the dragonfly will travel 1,056 miles.
Mathematics
1 answer:
Anestetic [448]3 years ago
4 0

Answer:

Based on the graph, what is the dependent variable, the equation relating the two variables, and how far will the dragonfly travel in 24 hours if it continues to fly at the same speed?

The dependent variable is time, the equation is y = 22x, and the dragonfly will travel 528 miles.

The dependent variable is time, the equation is x = 22y, and the dragonfly will travel 1,056 miles.

The dependent variable is distance, the equation is y = 22x, and the dragonfly will travel 528 miles.

The dependent variable is distance, the equation is x = 22y, and the dragonfly will travel 1,056 miles.

Step-by-step explanation:

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3 years ago
In evaluating a double integral over a region D, a sum of iterated integrals was obtained as follows:
BabaBlast [244]

Answer

a=0, b=2

g_1(x)=\frac{5x}{2},  g_2(x)=7-x

Step-by-step explanation:

Given that

\int \int   Df(x,y)dA=\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy+\int_5^7\int_0^{7-y} f(x,y)dxdy\; \cdots (i)

For the term  \int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy.

Limits for x is from x=0 to x=\frac {2y}{5} and for y is from y=0 to y=5  and the region D, for this double integration is the shaded region as shown in graph 1.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=\frac{5x}{2} to y=5 and limits of x become from x=0 to x=2 as shown in graph 2.

So, on reversing the order of integration, this double integration can be written as

\int_0 ^5\int _0 ^ {\frac {2y}{5}} f(x,y)dxdy=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx\; \cdots (ii)

Similarly, for the other term  \int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy.

Limits for x is from x=0 to x=7-y and limits for y is from y=5 to y=7  and the region D, for this double integration is the shaded region as shown in graph 3.

Now, reverse the order of integration, first integrate with respect to y then with respect to x . So, the limits of y become from y=5 to y=7-x and limits of x become from x=0 to x=2 as shown in graph 4.

So, on reversing the order of integration, this double integration can be written as

\int_5 ^7\int _0 ^ {7-y} f(x,y)dxdy=\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx\;\cdots (iii)

Hence, from equations (i), (ii) and (iii) , on reversing the order of integration, the required expression is

\int \int   Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^5 f(x,y)dydx+\int_0 ^2\int _5 ^ {7-x} f(x,y)dydx

\Rightarrow \int \int   Df(x,y)dA=\int_0 ^2\left(\int _ {\frac {5x}{2}}^5 f(x,y)+\int _5 ^ {7-x} f(x,y)\right)dydx

\Rightarrow \int \int   Df(x,y)dA=\int_0 ^2\int _ {\frac {5x}{2}}^{7-x} f(x,y)dydx\; \cdots (iv)

Now, compare the RHS of the equation (iv) with

\int_a^b\int_{g_1(x)}^{g_2(x)} f(x,y)dydx

We have,

a=0, b=2, g_1(x)=\frac{5x}{2} and g_2(x)=7-x.

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3 years ago
Examine the properties listed below. Determine which of the following properties are true for all parallelograms. Select all tha
vlada-n [284]
I’m not sure if you can do it
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The question is below:
Sonbull [250]
<h3>Hello There!!</h3><h2 /><h3><u>Given</u></h3>

3(x - 2) + 7x =  \frac{1}{2} (6x - 2)

<h3><u>Solving </u><u>It</u></h3>

3(x - 2) + 7x =  \frac{1}{2} (6x - 2)  \\  \\  \implies3x - 6 + 7x =  ([\frac{1}{2}   \times 6 \: x] -  [\frac{1}{2}  \times 2]) \\ \\   \implies10x - 6  =  ([\frac{1}{ \cancel2}   \times \cancel 6 \: x] -  [\frac{1}{ \cancel2}  \times  \cancel2]) \\  \\  \implies 10x - 6 = 3x - 1 \\  \\  \fbox{Bringing (3x )to left side whereas(  - 6 )in right side} \\  \\  \implies10x - 3x =  - 1 + 6 \\  \\  \implies7x = 5  \\  \\ \therefore x =  \frac{5}{7}

The Solution is = \frac{5}{7}

\text\red{One Solution set is possible.}

<h3>Hope This Helps</h3>
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The best way to plot them is by month.

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So, the coordinates would be 0, 110 1, 115 2, 120 3, 125

The month will be in the x axis and your money will be the Y axis 

7 0
3 years ago
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