Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Answer: 70.8%
56 divided by 79= 0.708
0.708x100=70.8
Answer:
g(x + 7) = 11x + 80
g(x) + g(7) = 11x + 83
Step-by-step explanation:
g(x + 7) = 11(x + 7) + 3 = 11x + 77 + 3 = 11x + 80
g(x) + g(7) = 11x + 3 + 11(7) + 3 = 11x + 3 + 77 + 3 = 11x + 83
Answer:
the slope is 4/1 because it's 4x and the y intercept is -4
The coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4) is 
Explanation :
the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)
Apply section formula to find coordinates of point Q

Ratio m:n is 2:3 and point R is (x1,y1) , point S is (x2,y2)
Substitute all the values inside the formula

The coordinates of point Q is 
Learn more : brainly.com/question/13878373