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Elis [28]
3 years ago
15

Select all equations that have graphs with the same y-intercept.

Mathematics
2 answers:
11111nata11111 [884]3 years ago
5 0

Answer:

A, D, E, F

Step-by-step explanation:

They all have the same y-intercept -8.

The formula is like this y = mx + b

m = slope

b = y-intercept

x = input

y = output

salantis [7]3 years ago
3 0
A D E F all have the same y-int which is -8

Y=mx+b
B is the y intercept
M is the slope
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What is the value of x after these statements if the starting value of x is 3.
kolbaska11 [484]
[A]
3^{2}=9
5^{3}=125
9\neq25

Ignore


[B]
3^{2} = 9
9 \ \textgreater \  3
Yes

3^{3}=27
4( 3^{2})=36

27 \ \textless \  36
Yes

Therefore
x=3+2=5


[C]
4^{5}=1024

 5^{4}=625

1024\ \textless \ 625
No

5^{5}=3125

 5^{5}=3125

3125\ \textgreater \ 3125
No

Ignore


[D]
5^{5}=3125

 2^{5}=32

3125\ \textgreater \ 32
Yes

5^{2}=25
25\ \textless \ 11
No

Therefore
x=5+8=13


[E]
8\ \textgreater \ 7
Yes

Therefore
x = 13^{2}=169
4 0
3 years ago
Find the Area of the figure below, composed of a parallelogram and two semicircles. Round to the nearest tenths place.
Mila [183]

Step-by-step explanation:

the total area = the area of full circle + the area of parallelogram = (π ×(8/2)²) + (28×7)

= (3,14 ×16)+(196)

= 50,24 +196

= 246,24

= 246,2

7 0
3 years ago
A triangle has vertices at R(1, 1), S(-2,-4), and T-3, -3). The triangle is transformed according to the rule Ro, 270 What the c
notsponge [240]

Answer:

Based on the situation above and the choices provided the he coordinates of S should be (2,4) while the coordinates of R is (-1, 1), and for the T it should be (–3, 3). I hope the answer will help.

3 0
3 years ago
Graph the function r(x) = -1/4 |x|
Free_Kalibri [48]
Here is your function graphed

8 0
3 years ago
Graph the image of square CDEF after a reflection across the x-axis​
Rina8888 [55]

Answer:

If you have a general point (x, y), and you reflect it across the x-axis, the coordinates of the new point will be:

(x,-y)

So we only change the sign of the y-component.

Now, if we do a reflection across the x-axis of a whole figure, then we apply the reflection to all the points that make the figure.

Then, we could just apply the reflection to the vertices of the square, then graph the new vertices, and then connect them, that is equivalent to graph the image of the square after the reflection.

The original vertices are:

C = (-3, 7)

D = (0, 7)

E = (0, 10)

F = (-3, 10)

Now we apply the reflection, remember that this only changes the sign of the y-component, then the new vertices are:

C' = (-3, -7)

D' = (0, -7)

E' = (0, - 10)

F' = (0, - 10)

Now we need to graph these points and connect them to get the reflected figure, the image can be seen below.

5 0
2 years ago
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