Answer:
D. integrated development environment
Explanation:
Given that an integrated development environment is a form of computer software App that allows the users or programmers to develop a software App in a way the enables them to carry out different operations including source code development, build and test automation, and debugging activities.
For example NetBeans, Eclipse, IntelliJ, and Visual Studio.
Hence, in this case, the correct answer is "integrated development environment."
Answer: Answer below.
Explanation:
I'm not fully sure myself, so don't agree with me fully.
I believe what she may have done wrong is tell the technician about a "program." A program doesn't have to do anything with physical hardware.
Explanation:
A.)
we have two machines M1 and M2
cpi stands for clocks per instruction.
to get cpi for machine 1:
= we multiply frequencies with their corresponding M1 cycles and add everything up
50/100 x 1 = 0.5
20/100 x 2 = 0.4
30/100 x 3 = 0.9
CPI for M1 = 0.5 + 0.4 + 0.9 = 1.8
We find CPI for machine 2
we use the same formula we used for 1 above
50/100 x 2 = 1
20/100 x 3 = 0.6
30/100 x 4 = 1.2
CPI for m2 = 1 + 0.6 + 1.2 = 2.8
B.)
CPU execution time for m1 and m2
this is calculated by using the formula;
I * CPI/clock cycle time
execution time for A:
= I * 1.8/60X10⁶
= I x 30 nsec
execution time b:
I x 2.8/80x10⁶
= I x 35 nsec
1.
name = input("Enter your name: ")
num1 = int(input("Hello "+name+ ", enter an integer: "))
num2 = int(input(name+", enter another integer: "))
try:
if num1 % num2 == 0:
print("The first number is divisible by the second number")
else:
print("The first number is not divisible by the second number")
except ZeroDivisionError:
print("The first number is not divisible by the second number")
try:
if num2 % num1 == 0:
print("The second number is divisible by the first number")
else:
print("The second number is not divisible by the first number")
except ZeroDivisionError:
print("The second number is not divisible by the first number")
2.
import random, math
num1 = float(input("Enter a small decimal number: "))
num2 = float(input("Enter a large decimal number: "))
r = round(random.uniform(num1, num2), 2)
print("The volume of a sphere with radius " + str(r) + " is " + str(round(((4 / 3) * math.pi * (r ** 3)), 2)))
I hope this helps!
B. A generated report will include all records that a query fetches.
