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12345 [234]
2 years ago
7

Draw

Computers and Technology
1 answer:
-BARSIC- [3]2 years ago
3 0

Answer:

it is true,a blank document appears with the name Document 1

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1. Write a recursive method to determine if a character is in a list of characters in O(logN) time. Mathematically prove (as we
sergeinik [125]

Answer:

1)

public class BinarySearch {

// Returns index of x if it is present in arr[l..

// r], else return -1

int binarySearch(char arr[], int l, int r, char x)

{

if (r >= l) {

int mid = l + (r - l) / 2;

 

// If the element is present at the

// middle itself

if (arr[mid] == x)

return mid;

 

// If element is smaller than mid, then

// it can only be present in left subarray

if (arr[mid] > x)

return binarySearch(arr, l, mid - 1, x);

 

// Else the element can only be present

// in right subarray

return binarySearch(arr, mid + 1, r, x);

}

 

// We reach here when element is not present

// in array

return -1;

}

 

// Driver method to test above

public static void main(String args[])

{

BinarySearch ob = new BinarySearch();

char arr[] = {'a','c','e','f','g','h'};

int n = arr.length;

char x = 'g';

int result = ob.binarySearch(arr, 0, n - 1, x);

if (result == -1)

System.out.println("Character not present");

else

System.out.println("Character found at index " + result);

}

}

2)

import java.io.*;

import java.util.*;

public class Test{

public static boolean checksame(String s)

{

 

Stack<Integer> stack= new Stack<Integer>();

for(int i=0;i<s.length();i++)

{

if(s.charAt(i)=='0')

{

if(stack.empty()==false)

{

if((Integer)stack.peek()==1)

stack.pop();

else

stack.push(0);

}

else

{

stack.push(0);

}

}

else if(s.charAt(i)=='1')

{

if(stack.empty()==false)

{

if((Integer)stack.peek()==0)

stack.pop();

 

else

stack.push(1);

}

else

{

stack.push(1);

}

 

}

}

return stack.empty();

}

public static void main(String []args){

System.out.println(checksame("a0w1220"));

}

}

Explanation:

5 0
3 years ago
A client is looking to maximize value from its Cloud investments by baselining, profiling, and prioritizing its human capital ne
barxatty [35]

myNav is to be present inn the Accenture software. It aim is to helps companies manage the human, technology and business dimensions of cloud change. The myNav module that will help this client is Cloud Advisor.

Cloud Advisor is simply known to be one of the many modules within the myNav platform. It was set up to handle the difficulties of cloud for digital transformation.

These Advisors are  known worldwide community of technical resources. They have a thorough  knowledge of cloud technologies and practices.

Their mission is to know the trends, regulatory implications, and our clients' needs so as to help them to set goals and create plans to achieve their desired outcome.

Learn more from

brainly.com/question/24918185

3 0
2 years ago
To provide for unobtrusive validation, you can install the ____________________ package for unobtrusive validation.
NARA [144]

Answer:

AspNet.ScriptManager.jQuery?

Explanation:

Unobtrusive validation means we can perform a simple client-side validation without writing a lot of validation code by adding suitable attributes and also by including the suitable script files.

One of the benefits of using a unobtrusive validation is that it help to reduce the amount of the Java script that is generated. We can install the AspNet.ScriptManager.jQuery? for the unobtrusive validation.

When the unobtrusive validation is used, validation of the client is being performed by using a JavaScript library.

4 0
3 years ago
Whats the best way to get into a computers programming to get past firewalls
raketka [301]

you can use the software psiphon

6 0
3 years ago
Read 2 more answers
What are the reasons why is it necessary to evaluate online sources and content?
marissa [1.9K]
1) You don't know if the source is reliable. 
2) It is better to cite reliable sources so.
7 0
3 years ago
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