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maksim [4K]
2 years ago
8

For any number n>1 is |(3/4+2/3i)^n|

Mathematics
1 answer:
sasho [114]2 years ago
6 0

The for any number n>1 is |(3/4+2/3i)^n| greater than 1 after simplifying the complex number.

<h3>What is a complex number?</h3>

It is defined as the number which can be written as x+iy where x is the real number or real part of the complex number and y is the imaginary part of the complex number and i is the iota which is nothing but a square root of -1.

We have a complex number:

= \rm |(\dfrac{2}{3}+\dfrac{3}{4}i)^n|\\\\\\= \rm |(\dfrac{8+9i}{12})^n|\\\\\\= \rm |\dfrac{(8+9i)^n}{12^n}|\\\\

Here n>1

Plug n = 2

= \rm |\dfrac{(8+9i)^2}{12^2}|\\\\

= 145/144

= 1.0069

Which is greater than 1.

Thus, the for any number n>1 is |(3/4+2/3i)^n| greater than 1 after simplifying the complex number.

Learn more about the complex number here:

brainly.com/question/10251853

#SPJ1

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Answer:

\frac{1}{8xy \sqrt{y} }

Step-by-step explanation:

(64 {x}^{2}  {y}^{3} )^{  - \frac{ 1 }{2} }  \\  \\  =  \frac{1}{(64 {x}^{2}  {y}^{3} )^{\frac{ 1 }{2} } }  \\  \\  =  \frac{1}{ \sqrt{64 {x}^{2}  {y}^{3}} }  \\  \\  =  \frac{1}{ \sqrt{ {(8xy)}^{2} y} }  \\  \\  =  \frac{1}{8xy \sqrt{y} }

3 0
2 years ago
The side lengths of a triangle are 6, 8, and 12. Is this a right triangle?
gizmo_the_mogwai [7]
<h2><u>D.</u></h2><h3>It's incorrect, because 6 squared = 36, 8 squared = 64, add them together and you get 100. 12 squared does NOT equal 100, it equals 144.</h3>

<em>(To find the hypotenuse {longest side of the triangle}, you square the two short sides, add them together, and finally, divide it by the provided number, and see if the number matches the provided number's square.)</em>

<h3>Brainly if correct and Thanks!</h3>
8 0
3 years ago
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Step-by-step explanation:

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3 years ago
Round to the whole number: 46.94= and 7.09=. What is 10/40=.
frez [133]
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7.09 ≈ 7

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3 years ago
X/y for x= 2/3 and y= 6/7
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