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3 years ago

Please can someone help me with this question and a few more.. I will give brainliest and full ratings.

Mathematics

2 answers:

-BARSIC- [3]3 years ago

8 0

In y = mx + b form, the slope will be in the m position and the y int will be in the b position

y = 6x - 5.....the slope is 6. A parallel line will have the same slope

with a y int of 7....

y = 6x + 7 <===

lesya692 [45]3 years ago

8 0

Parallel lines have same slope so the required equation will be y = 6x + something ( 6 is the slope)

the something is the y intercept which is 7

So its A

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Triangle ABC has side length of 14, 8 and 10.4 what are the possible side lengths of a triangle DEF if ABC is similar to DEF

defon

Answer:

<em>DEF can have possible side lengths of 28, 16, 20.8</em>

Step-by-step explanation:

<u>Triangle Similarity</u>

If the three sides of two triangles have the same proportion, the triangles are similar (SSS theorem).

Triangle ABC has side lengths of 14, 8, and 10.4.

Any other triangle whose side lengths are the same lengths of ABC multiplied by a constant scale factor is similar to ABC.

For example, select scale factor 2. Thus, the triangle of side lengths 2*14=28, 2*8=16, and 2*10.4=20.8 is similar:

DEF can have possible side lengths of 28, 16, 20.8

Any other scale factor will do.

8 0

2 years ago

12 Kendrick wants to build a slide for his son in the backyard. He buys a

pantera1 [17]

5^2 + x^2=8^2
25+x^2=64
X=6.2

6 0

2 years ago

Help? please.........

UkoKoshka [18]

Answer: 60°

Step-by-step explanation: A straight angle is 180°

180°- 120° = 60°

8 0

2 years ago

A parabola can be drawn given a focus of

Volgvan

Answer:

$y=-\frac{1}{4}(x-2)^{2}+9$

Step-by-step explanation:

Any point on a given parabola is equidistant from focus and directrix.

Given:

Focus of the parabola is at $(2,8)$ .

Directrix of the parabola is $y=10$ .

Let $(x,y)$ be any point on the parabola. Then, from the definition of a parabola,

Distance of $(x,y)$ from focus = Distance of $(x,y)$ from directrix.

Therefore,

$\sqrt{(x-2)^{2}+(y-8)^{2}}=|y-10|$

Squaring both sides, we get

$(x-2)^{2}+(y-8)^{2}=(y-10)^{2}\\(x-2)^{2}=(y-10)^{2}-(y-8)^{2}\\(x-2)^{2}=(y-10+y-8)(y-10-(y-8))...............[\because a^{2}-b^{2}=(a+b)(a-b)]\\(x-2)^{2}=(2y-18)(y-10-y+8)\\(x-2)^{2}=2(y-9)(-2)\\(x-2)^{2}=-4(y-9)\\y-9=-\frac{1}{4}(x-2)^{2}\\y=-\frac{1}{4}(x-2)^{2}+9$

Hence, the equation of the parabola is $y=-\frac{1}{4}(x-2)^{2}+9$ .

4 0

3 years ago

Consider the equation 21 = m + 14 1/6. Which step will help to solve this equation? A add 14 1/6 on both sides of the equation.

Furkat [3]

Answer:

B. subtract

Step-by-step explanation:

Subtracting is the opposite of adding which is what is originally in the equation, by subtracting you are canceling out the 14 1/6

7 0

2 years ago