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3 years ago

I don't know how start this, I don't understand it too. Please help, please show work too. Thank you.

Mathematics

1 answer:

neonofarm [45]3 years ago

4 0

I’m not positive but I’m thinking you are supposed to draw the door and window or color them in and each small square counts as a foot so like 7 of the squares is 7 feet so after you color in the door and window it will show what part needs to be painted

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A day in the month of January is randomly selected What is the probability of selecting a perfect square?

Stels [109]

Answer:

5/31

Step-by-step explanation:

there are 31 days in January 5 of those are prefect squares (1,4,9,16,25)

7 0

3 years ago

Read 2 more answers

Perform the following operations and write the answers in radical form.

strojnjashka [21]

Given:

Part A: $\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}$

Part B: $3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}$

To find:

The simplified radical form.

Solution:

Part A: $\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}$

$\sqrt{98}=\sqrt{7^2 \times 2} =7 \sqrt{2}$

$\sqrt{18}=\sqrt{3^2 \times 2} =3 \sqrt{2}$

Substitute these in the given expression.

$\sqrt{7}+\sqrt{3}+\sqrt{98}-\sqrt{18}=\sqrt{7}+\sqrt{3}+7\sqrt{ 2}-3\sqrt{ 2}$

Add or subtract the coefficient of same radical.

$=\sqrt{7}+\sqrt{3}+(7-3)\sqrt{ 2}$

$=\sqrt{7}+\sqrt{3}+4\sqrt{ 2}$

Part B: $3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}$

$2 \sqrt{121}=2\sqrt{11^2}$

$=2\times 11$

= 22

$3 \sqrt{90}=3\sqrt{3^2 \times 10}$

$=3\times 3 \sqrt{10}$

$=9 \sqrt{10}$

Substitute these in the given expression.

$3 \sqrt{5}-3 \sqrt{11}+2 \sqrt{121}-3 \sqrt{90}=3 \sqrt{5}-3 \sqrt{11}+22-9 \sqrt{10}$

8 0

3 years ago

Ella simplifies (3b+4r)+(-2b-r) and says the result is b+5r. What error did Ella make?

VashaNatasha [74]

The correct answer is (D).
(3b + 4r) + (-2b - r) = (3b - 2b) + (4r - r) = b + 3r
not
b + 5r
* Ella added (4r + r) instead subtracting (4r - r), thus she got the wrong answer.

7 0

3 years ago

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Someone please answer ! I have no clue what the answer is :/

VLD [36.1K]

The answer to the question