If x represents the width of the poster (including borders), the area of the finished poster can be written as
.. a = x*(390/(x -10) +8)
.. = 8x +390 +3900/(x -10)
Then the derivative with respect to x is
.. da/dx = 8 -3900/(x -10)^2
This is zero at the minimum area, where
.. x = √(3900/8) +10 ≈ 32.08 . . . . cm
The height is then
.. 390/(x -10) +8 = 8 +2√78 ≈ 25.66 . . . . cm
The poster with the smallest area is 32.08 cm wide by 25.66 cm tall.
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In these "border" problems, the smallest area will have the same overall dimension ratio that the borders have. Here, the poster is 10/8 = 1.25 times as wide as it is high.
No it is NOT possible - that would mean the final angle would also have to be ninety degrees making it a square or rectangle. :)
Your answer is 26,453
Although I don't feel as if this is a homework question, I will still show the work.
Work:
Step 1: 999 + 999 = 1,998
Step 2: 1,998 + 999 = 2,997
Step 3: 2,997 + 23,456 = 26,453
Hope I was able to help! :)
Answer:
6
Step-by-step explanation:
(a^3 - b^3)/5
Let a =2 and b = -3
(2^3 - (-3)^3)/5
Exponents inside the parentheses
(8 - -27)/5
Subtracting a negative is like adding
(8+27)/5
Finish adding inside the parentheses
35/5
Divide
7
