All categories

3 years ago

Pls answer

Mathematics

1 answer:

cluponka [151]3 years ago

6 0

Answer:

$8.49\ units$

Step-by-step explanation:

we know that

The Pythagorean Theorem states that in a right triangle

$c^2=a^2+b^2$

where

c is the greater side (the hypotenuse)

a and b are the legs

In this problem

Let

c=AB ---> distance from point A to point B

a ---> the difference of the x-coordinates both points

b ---> the difference of the y-coordinates both points

$a=1-(-5)=6\ units\\b=6-0=6\ units$

substitute

$AB^2=6^2+6^2$

$AB^2=72$

$AB=\sqrt{72}\ units$

$AB=8.49\ units$

You might be interested in

On a math test 12 students earned an a this number is exactly 25% of the total number of students in the class how many students

statuscvo [17]

Answer:

48 students.

Step-by-step explanation:

25% of total students = 12

suppose,

total students= x

so,

25% of x=12

(25/100)*x=12

25*x=(12*100)

x=1200/25

x=48

therefore,

x= total students= 48.

7 0

3 years ago

How do you do this question? 24 is what percent of 32?

Eddi Din [679]

24 = x% * 32

24= x/100 * 32

Multiply 100 on both sides.

2400 = x * 32

32x = 2400

Divide 32 on both sides.

x = 2400/32

x = 75

75 percent of 32 is 24

6 0

3 years ago

Read 2 more answers

What is the area of the rectangle? shoe your work! do not round anything until the very end and round your final answer to the t

weeeeeb [17]

Answer:

The area of the rectangle is 42 units^2

Step-by-step explanation:

we know that

The area of rectangle is equal to

$A=LW$

In this problem

AB=DC

BC=AD

see the attached figure with letters to better understand the problem

we have that

$L=BC\\W=AB$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have the points

$A(2,-1),B(5,2),C(12,-5),D(9,-8)$

Find out the distance BC

we have

$B(5,2),C(12,-5)$

substitute in the formula

$d=\sqrt{(-5-2)^{2}+(12-5)^{2}}$

$d=\sqrt{(-7)^{2}+(7)^{2}}$

$d_B_C=\sqrt{98}\ units$

Find out the distance AB

we have

$A(2,-1),B(5,2)$

substitute in the formula

$d=\sqrt{(2+1)^{2}+(5-2)^{2}}$

$d=\sqrt{(3)^{2}+(3)^{2}}$

$d_A_B=\sqrt{18}\ units$

Find out the area

$A=(L)(W)$

we have

$L=d_B_C=\sqrt{98}\ units$

$W=d_A_B=\sqrt{18}\ units$

substitute

$A=(\sqrt{98})(\sqrt{18})=42.0\ units^2$

4 0

3 years ago

Solve this inequality. 7.2-3w<4.5

zlopas [31]

Answer:

w>0.9

Step-by-step explanation:

7.2-3w<4.5

-7.2 -7.2

-3w<-2.7

/-3 /-3

w>0.9

The inequality switches when divided by a negative.

-hope it helps

8 0

2 years ago

Read 2 more answers

A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than

aleksklad [387]

Answer:

The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

The sample size is $n = 13$

The sample mean is $\= x = 9.63$

The standard deviation is $s = 0.585$

The significance level is $\alpha = 0.05$

The Null Hypothesis is $H_o : \mu = 0$

The Alternative Hypothesis is $H_a = \mu < 10$

The test statistic is mathematically represented as

$t = \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }$

Substituting values

$t = \frac{9.63 - 10 }{\frac{0.585}{\sqrt{13} } }$

$t = - 2.280$

Now the critical value for $\alpha$ is

$t_{\alpha } = 1.645$

This obtained from the critical value table

So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

The conclusion is that the researcher was correct

6 0

3 years ago