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Naily [24]
3 years ago
6

Pls answer

Mathematics
1 answer:
cluponka [151]3 years ago
6 0

Answer:

8.49\ units

Step-by-step explanation:

we know that

The Pythagorean Theorem states that in a right triangle

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs

In this problem

Let

c=AB ---> distance from point A to point B

a ---> the difference of the x-coordinates both points

b ---> the difference of the y-coordinates both points

so

a=1-(-5)=6\ units\\b=6-0=6\ units

substitute

AB^2=6^2+6^2

AB^2=72

AB=\sqrt{72}\ units

AB=8.49\ units

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how many different four letter permutations can be formed using four letters out of the first 12 in the alphabet?
Verizon [17]

Answer:

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

Step-by-step explanation:

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

Permutations of four letters from a set of 12 letters. So

P_{(12,4)} = \frac{12!}{(12-4)!} = 11800

11,800 different four letter permutations can be formed using four letters out of the first 12 in the alphabet

3 0
3 years ago
Can i get some help please??? Thanks!!!!
Varvara68 [4.7K]

Answer:

9.6

Step-by-step explanation:

d =  \sqrt{ {8}^{2}  +  {2}^{2} +  {5}^{2}  }  \\  =  \sqrt{64 + 4 + 25}  \\  =  \sqrt{93}  \\  = 9.64365076 \\  = 9.6

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3 years ago
Please help me with this question.
lara31 [8.8K]
The answer would be 66
3 0
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