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Naily [24]
2 years ago
6

Pls answer

Mathematics
1 answer:
cluponka [151]2 years ago
6 0

Answer:

8.49\ units

Step-by-step explanation:

we know that

The Pythagorean Theorem states that in a right triangle

c^2=a^2+b^2

where

c is the greater side (the hypotenuse)

a and b are the legs

In this problem

Let

c=AB ---> distance from point A to point B

a ---> the difference of the x-coordinates both points

b ---> the difference of the y-coordinates both points

so

a=1-(-5)=6\ units\\b=6-0=6\ units

substitute

AB^2=6^2+6^2

AB^2=72

AB=\sqrt{72}\ units

AB=8.49\ units

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Select the correct choice below and fill in any answer boxes in your choice
soldier1979 [14.2K]

So we need to solve:

\frac{13}{y}+\frac{5}{y}=3

First is important to note that both terms on the left side of the equation have a common factor because they are both divided by y. Then:

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Then:

\begin{gathered} \frac{18}{y}=3 \\ 18=3y \\ \frac{18}{3}=y \\ y=\frac{18}{3}=6 \end{gathered}

So the solution is y=6. Then option A is correct and you need to write the 6 between the symbols { }.

4 0
1 year ago
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Fantom [35]

Answer:

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Step-by-step explanation:

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3 years ago
PQ= 2x +1 and QR= 5x - 44; find PQ
Lena [83]

2x+1=5x-44 that would be your equation

next start to simplify 

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6 0
2 years ago
Read 2 more answers
Irina rode her bike to work at an average speed of 16 miles per hour. It started to rain, so she got a ride home along the same
Sedaia [141]

Answer:

0.7 hours

Step-by-step explanation:

Given that Irina was able to make the same distance from work to home in 0.4 of an hour at 27 miles per hour, we can use this rate and time to find the distance she travels to and from work using the general formula:

d = rt, where d=distance, r = rate and t = time

d = 27(0.4) = 10.8 miles

Since the distance from Irina's home to work is 10.8 miles, we can again use the formula 'd = rt' to find the time it takes her to bike to work at a rate of 16 miles per hour and solving for time, 't':

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3 0
3 years ago
Sarah borrowed some money from her father at a simple interest rate of 5.5% to pay for her college tuition. At the end of the ye
gavmur [86]
\bf ~~~~~~ \textit{Simple Interest Earned Amount}
\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &\$2555\\
P=\textit{original amount deposited}\\
r=rate\to 5.5\%\to \frac{5.5}{100}\to &0.055\\
t=years\to &1
\end{cases}
\\\\\\
2555=P[1+(0.055)(1)]\implies \cfrac{2555}{1+(0.055)(1)}=P
\\\\\\
\cfrac{2555}{1.055}=P\implies 2421.800947867 \approx P
4 0
3 years ago
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