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Help 8th grade math need answers quick

stepladder [879]

Answer:

A few examples:

0. 0

1. Undefined

2. -3/5

3. Undefined

...

7. 493

8. 5/2

....

Learn how to find the slope below for the other problems.

Step-by-step explanation:

Slope is the rate of change for a linear function. It is found by subtracting the y values of two point on the line and dividing that difference by the difference of the x values of the points.

It can also be found using the formula y=mx+b known as the slope intercept form.

Here are a few examples:

0. This is a horizontal line which always has slope 0.

1. This is a vertical line which always has slope undefined.

2. Find two points that cross through a grid line intersection The line appears to cross them at (5,3) and (0,6). Count the unit squares between the two by counting up 3 and over to the left 5. Because it is left it is negative. The slope is -3/5

3. To find the slope, use the slope formula:

$\frac{y_2-y_1}{x_2-x_1}=\frac{6--4}{-2--2}=\frac{6+4}{-2+2}=\frac{10}{0}=undefined$

Since we can't divide by 0, it is undefined.

7. y=493x-257 follows the formula y=mx+b where m is the slope. m=493. The slope is 493.

8. Covert the equation into y=mx+b by rearranging the terms using y=mx+b.

5x-2y=48

-2y=48-5x

y=5/2 x -24

So the slope is 5/2.

8 0

3 years ago

The rate of change of the number of mountain lions N(t) in a population is directly proportional to 725 - N(t), where t is the t

wolverine [178]

Answer:

a) The implied differential equation is $\frac{dN}{725 - N} = kdt$

b) The general equation is $N = 725 - C e^{-kt}$

c) The particular equation is $N = 725 - 325 e^{-0.49t}$

d) The population when t = 5, N(5) = 697 = 700( to the nearest 50)

Step-by-step explanation:

The rate of change of N(t) can be written as dN/dt

According to the question, $\frac{dN}{dt} \alpha (725 - N(t))$

$\frac{dN}{dt} = k (725 - N)\\\frac{dN}{725 - N} = kdt$

Integrating both sides of the equation

$\int {\frac{1 }{725 - N}} \, dN = \int {k} \, dt\\- ln (725 - N) = kt + C\\ ln (725 - N) = -(kt + C)\\725 - N = e^{-(kt + C)} \\725 - N = e^{-kt} * e^{-C} \\725 - N = C e^{-kt}\\N = 725 - C e^{-kt}$