Based on the given question above, the correct answer would be the fourth option. The <span>circumstance that the cross section can be a non-rectangular parallelogram is that, </span><span>when the plane makes an acute angle to the base and intersects three vertical faces. Hope this answers the question. </span>
The arc is called B) Circle
Answer:
(4, –1, 3)
What is the solution to the following system? (3, –1, 4) (4, 1, 3) (4, –1, 3) (3, 1, 4
