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Liono4ka [1.6K]
3 years ago
10

60 = 5(1.07)^x

Mathematics
1 answer:
olga_2 [115]3 years ago
7 0

Given:

The given equation is

60=5(1.07)^x

To find:

The initial value and growth/decay factor.

Solution:

The general exponential growth/decay model is

y=a(1+r)^x     ...(i)

where, a is initial value, if r>0, then |r| is growth factor, if r<0, then |r| is decay factor and x is time.

We have,

60=5(1.07)^x

It can be written as

60=5(1+0.07)^x        ...(ii)

On comparing (i) and (ii), we get

a=5\text{ and }r=0.07

Here, initial value is 5 and growth factor is 0.07, i.e., 7%.

Therefore, the correct option for first question is d and correct option for second question is a.

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3 years ago
Write a polynomial function f of least degree that has rational coefficients, a leading coefficient of 1, and the zeros 4 and 3−
Neko [114]

Answer:

P(x) = x^3 - 10x^2+ 34x-40

Step-by-step explanation:

Given

p =1 -- Leading coefficient

Zeros: 4\ and\ 3  - i

Required

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Represent the zeros with a and b

Such that

a = 4

b = 3 - i

The polynomial is:

P(x) = p * (x - a) * (x - b)

P(x) = 1 * (x - 4) * (x - (3 - i))

However, to solve further: We need to symmetrise over 3-i  and its conjugate

P(x) = 1 * (x - 4) * (x - (3 - i))* (x - (3 + i))

P(x) =  (x - 4) * (x - (3 - i))* (x - (3 + i))\\\\

To define a suitable function, the expression becomes

P(x) =  (x - 4) * ((x - 3)^2+1)

P(x) =  (x - 4) * ((x - 3)(x - 3)+1)

P(x) =  (x - 4) * (x^2 - 6x + 9+1)

P(x) =  (x - 4) * (x^2 - 6x +10)

Open bracket

P(x) = x^3 - 6x^2 +10x - 4x^2 + 24x-40

P(x) = x^3 - 6x^2  - 4x^2+10x + 24x-40

P(x) = x^3 - 10x^2+ 34x-40

5 0
3 years ago
Evaluate log (0.3).<br> Round your answer to the nearest thousandth.
djverab [1.8K]

Answer:

-0.523

Step-by-step explanation:

log(a/b)=loga-logb

log (0.3) can be written as log (3/10).

=log(3/10)

=log3-log10

=0.477-1 (log3=0.477 and log10=1)

= -0.523

5 0
3 years ago
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