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3 years ago

15

There are four different answers to the mathematical question: 3 + 2 * 3^2 = ?

1 answer:

erastovalidia [21]3 years ago

3 0

Answer:

The order in which you solve the operations will provide different results and to be able to get the right answer you have to be familiar with the order of operations to know the appropiate steps to solve an operation. According to the order of operations in mathematics, exponents are given precedence over addition and multiplication. Because of that, the exponent is the first you have to solve.

3 + 2 * 3^2

3+2*9

Then, mutiplication is given precedence over addition:

3+18

Now, you can solve the addition and the result is: 21

Because of this, the answer is:

• 3 +( 2 * (3^2)) = 21

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A.Adjacent <br> B.Vertical<br> C.None<br> D.Complementary

dimaraw [331]

Answer:

A. Adjacent

Step-by-step explanation:

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3 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

<em>Correct answer:</em>

<em>A. I and II</em>

<em></em>

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3 years ago

How can you solve problems involving direct variation?

never [62]

Answer:

Solving a Direct Variation Problem

Write the variation equation: y = kx or k = y/x.

Substitute in for the given values and find the value of k.

Rewrite the variation equation: y = kx with the known value of k.

Substitute the remaining values and find the unknown.

Step-by-step explanation:

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3 years ago

dimaraw [331]

-m - (7/8) = -10

m = 10 - (7/8)

LCM = 8

m = (80 - 7)/8

m = 72/8

m = 9

hope it helps...!!!

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avanturin [10]

Sender would be 4 x 7 divided by 15

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2 years ago