Answer:
C) The solution for the given system of equations are A(0,-5) and B(-4,3)
Step-by-step explanation:
The given system of equation are : 
from equation 2, we get y = -5 - 2x .
Put the above value of y in the equation (1).
We get: 
By ALGEBRAIC IDENTITY:
or, 
or, 
⇒ x = 0 or, x = -20/5 = -4
So, the possible values for x are: x = 0 or x = -4
If x = 0, y = -5-2x = -5-2(0) = -5
and if x = -4, y = -5 -2(-4) = -5 + 8 = 3
Hence, the solution for the given system of equations are A(0,-5) and B(-4,3)
Question 1)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
F(G(x)) = 3(2x - 3)^2 + 1
F(G(x)) =3(4x^2 - 12x + 9) + 1
F(G(x)) = 12x^2 - 36x + 27 + 1
F(G(x)) =12x^2 - 36x + 28
Question 2)
Given: F(x) = 3x^2 + 1, G(x) = 2x - 3, H(x) = x
H -1 (x) = x (inverse)
Any odd number can be expressed by 2n+1.
For example,
2n+1=111
2n=110
n=110/2=55
means that 111 is 2n+1 for n=55
Thus if an odd number is 2a+1, the next few numbers are as follows:
2a+1, 2a+2, 2a+3, 2a+4, 2a+5
So 2a+1, 2a+3 and 2a+5 are 3 consecutive odd numbers.
Back to our problem:
three consecutive odd numbers whose sum is 63 are:
(2n+1)+(2n+3)+(2n+5)=63
6n+9=63
6n=63-9=54
n=54/6=9
2n+1=2*9+1=18+1=19, the 2 next odd numbers are 21 and 23
Answer: 19, 21, 23
A is 0.025 from what i worked out, I hope it is correct :)
Answer:
$190
8
Step-by-step explanation:
